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  • 大小: 4KB
    文件類型: .c
    金幣: 1
    下載: 0 次
    發布日期: 2021-06-04
  • 語言: C/C++
  • 標簽: 農夫過河??

資源簡介

數據結構,農夫過河。詳細講述過河 #include //0代表在河的這邊;1代表在河的對岸 struct Condition{ int farmer; int wolf; int sheep; int cabbage; }; struct Condition conditions[100];//結構體條件數組 char * action [100]; void takeWolfOver(int i) //把狼來過去 { action[i]="把狼過去.---->對岸"; conditions[i+1].wolf=1; conditions[i+1].sheep=conditions[i].sheep; conditions[i+1].cabbage=conditions[i].cabbage; } void takeWolfBack(int i)/*把狼帶回來*/ { action[i]="帶狼回來.本岸對岸"; conditions[i+1].wolf=conditions[i].wolf; conditions[i+1].sheep=1; conditions[i+1].cabbage=conditions[i].cabbage; } void takeSheepBack(int i)/*把羊帶回來*/ { action[i]="帶羊回來.本岸對岸"; conditions[i+1].wolf=conditions[i].wolf; conditions[i+1].sheep=conditions[i].sheep; conditions[i+1].cabbage=1; } void takeCabbageBack(int i)/*把菜帶回來*/ { action[i]="帶菜回來.本岸對岸"; conditions[i+1].wolf=conditions[i].wolf; conditions[i+1].sheep=conditions[i].sheep; conditions[i+1].cabbage=conditions[i].cabbage;/*全不動*/ } void getBackBarely(int i)/*返回時的情況*/ { action[i]="空手回來.本岸<---(barely)"; conditions[i+1].wolf=conditions[i].wolf; conditions[i+1].sheep=conditions[i].sheep; conditions[i+1].cabbage=conditions[i].cabbage; } void showSolution(int i)/*顯示解決方法*/ { int c; printf("\n"); printf("%s\n","解決辦法:"); for(c=0;c<i;c++) { printf("step%d:%s\n",c+1,action[c

資源截圖

代碼片段和文件信息

#include
//0代表在河的這邊;1代表在河的對岸
struct?Condition{
?int?farmer;
?int?wolf;
?int?sheep;
?int?cabbage;
};
struct?Condition?conditions[100];//結構體條件數組
char?*?action?[100];
void?takeWolfOver(int?i)
//把狼來過去
{
????action[i]=“把狼過去.---->對岸“;
????conditions[i+1].wolf=1;
????conditions[i+1].sheep=conditions[i].sheep;
????conditions[i+1].cabbage=conditions[i].cabbage;
}
void?takeWolfBack(int?i)/*把狼帶回來*/
{
????action[i]=“帶狼回來.本岸<---(wolf)“;
????conditions[i+1].wolf=0;
????conditions[i+1].sheep=conditions[i].sheep;
????conditions[i+1].cabbage=conditions[i].cabbage;
????}
void?takeSheepOver(int?i)/*把羊帶過去*/
{
????action[i]=“帶羊過去.(sheep)--->對岸“;
????conditions[i+1].wolf=conditions[i].wolf;
????conditions[i+1].sheep=1;
????conditions[i+1].cabbage=conditions[i].cabbage;
}
void?takeSheepBack(int?i)/*把羊帶回來*/
{
????action[i]=“帶羊回來.本岸<---(sheep)“;
????conditions[i+1].wolf=conditions[i].wolf;
????conditions[i+1].sheep=0;
????conditions[i+1].cabbage=conditions[i].cabbage;
}
void?takeCabbageOver(int?i)/*把菜帶過去*/
{
????action[i]=“帶菜過去.(cabbage)--->對岸“;
????conditions[i+1].wolf=conditions[i].wolf;
????conditions[i+1].sheep=conditions[i].sheep;
????conditions[i+1].cabbage=1;
}
void?takeCabbageBack(int?i)/*把菜帶回來*/
{
????action[i]=“帶菜回來.本岸<---(cabbage)“;
????conditions[i+1].wolf=conditions[i].wolf;
????conditions[i+1].sheep=conditions[i].sheep;
????conditions[i+1].cabbage=0;
}
void?getOverBarely(int?i)/*過河時的情況*/
{
????action[i]=“空手過去.(barely)--->對岸“;
????conditions[i+1].wolf=conditions[i].wolf;
????conditions[i+1].sheep=conditions[i].sheep;
????conditions[i+1].cabbage=conditions[i].cabbage;/*全不動*/
}
void?getBackBarely(int?i)/*返回時的情況*/
{
????action[i]=“空手回來.本岸<---(barely)“;
????conditions[i+1].wolf=conditions[i].wolf;
????conditions[i+1].sheep=conditions[i].sheep;
????conditions[i+1].cabbage=conditions[i].cabbage;
}
void?showSolution(int?i)/*顯示解決方法*/
{
????int?c;
????printf(“\n“);
????printf(“%s\n““解決辦法:“);
????for(c=0;c????{
????????printf(“step%d

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