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  • 大小: 12KB
    文件類型: .cpp
    金幣: 1
    下載: 0 次
    發布日期: 2021-06-05
  • 語言: C/C++
  • 標簽: C++class??

資源簡介

這是本人大二下學期課程設計的選題,有添加,刪除,修改,查詢,顯示等功能,一些輸入怪異的東東也已經排除,應該不錯,而且容易理解,對大家應該會有很大幫助!

資源截圖

代碼片段和文件信息

#include
#include
#include
#include
#include?
using?namespace?std;
class?book
{
public:
book(string?nam=“system“string?telenum=“system“string?addr=“system“string?q=“system“
string?p=“system“):?name(nam)telenumber(telenum)address(addr)qq(q)post(p){}
????char?inter_face();
????void?add_person();
void?del_person();
void?show_all();
void?alter();
void?select();
void?save_new();
void?save_new_1();
?????int?compare();
private:
string?name;
string?telenumber;
string?address;
string?qq;
string?post;
};

//登陸界面
char?book::inter_face()
{
ofstream?outData(“pbook.txt“ios::app);
outData.close();
????system(“cls“);
cout< cout<<“\t\t★★★★★★★★★★★★★★★★★★★★★★★★★★“<????????<<“\t\t◆????????????????????????????????????????????????◆“<????????<<“\t\t◆?????????????歡迎使用小小通訊錄?????????????????◆“<????????<<“\t\t◆????????????????????????????????????????????????◆“<????????<<“\t\t◆??????1.?添加新聯系人.??????4.?修改信息.????????◆“<????????<<“\t\t◆????????????????????????????????????????????????◆“<????????<<“\t\t◆??????2.?刪除聯系人.????????5.?查詢聯系人.??????◆“<????????<<“\t\t◆????????????????????????????????????????????????◆“<????????<<“\t\t◆??????3.?顯示所有聯系人.????6.?關閉通訊錄.??????◆“<????????<<“\t\t◆????????????????????????????????????????????????◆“<????????<<“\t\t★★★★★★★★★★★★★★★★★★★★★★★★★★“< < char?choose;
cin>>choose;
cout< return?choose;
}

//添加聯系人的信息
void?book::add_person()
{
do
{
cout<<“請輸入添加聯系人的信息:“< cout< cin>>name;
cout<<“號碼:“;
cin>>telenumber;
cout<<“地址:“;
cin>>address;
cout<<“??QQ:“;
cin>>qq;
cout<<“郵編:“;
cin>>post;
}
while(compare()==1);
save_new();??????????????
cout< system(“pause“);
}?

//保存信息
void?book::save_new()
{
ofstream?outData(“pbook.txt“ios::app);
if(!outData)
{
cerr<<“open?pbook.txt?error!“< exit(1);
}
else
{
outData< < ?outData.close();
}
}

int??book::compare()
{
ifstream?inData(“pbook.txt“ios::in);
if(!inData)
{
cerr<<“open?pbook.txt?error!“<???? exit(1);
}
string?name1;
string?telenumber1;
string?address1;
string?qq1;
string?post1;
for(int?i=0;i {
if(telenumber[i]<‘0‘||telenumber[i]>‘9‘)
{
???cout<<“您輸入的號碼字符應在0~9之間請重新輸入!“< ???inData.close();
???return?1;
}
}
for(int?j=0;j {
????if(post[j]<‘0‘||post[j]>‘9‘)
{
???cout<<“您輸入的郵編字符應在0~9之間請重新輸入!“< ???inData.close();
???return?1;
}
}
while(inData>>name1>>telenumber1>>address1>>qq1>>post1)
{
if(telenumber1==telenumber||qq1==qq)
{??
??cou

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