//編程實現RSA_1
#include
#include?
void?show（int?r[]）??????????//將二進制轉化為十六進制并輸出
{
	int?i;
	int?a[40];
	for（i=0;i<40;i++）
	{
		a[i]=r[i*4+0]*8+r[i*4+1]*4+r[i*4+2]*2+r[i*4+3]*1;
	????switch（a[i]）
		{
		case?0?:
			printf（“0“）;break;
		case?1?:?
			printf（“1“）;break;
		case?2?:
			printf（“2“）;break;
		case?3?:?
			printf（“3“）;break;
		case?4?:?
			printf（“4“）;break;
		case?5?:?
			printf（“5“）;break;
		case?6?:?
		????????printf（“6“）;break;
		case?7?:
			printf（“7“）;break;
		case?8?:?
			printf（“8“）;break;
		case?9?:?
			printf（“9“）;break;
		case?10?:
			printf（“a“）;break;
		case?11?:?
			printf（“b“）;break;
		case?12?:?
			printf（“c“）;break;
		case?13?:?
			printf（“d“）;break;
		case?14?:
			printf（“e“）;break;
		case?15?:?
			printf（“f“）;break;
		default:?break;
		}
		if（i%8==7）
				printf（“\n“）;
	}

}
void?rotl（int?a[]int?n）???//實現二進制a循環左移n位
{
	int?i;
	int?b[32];
????for（i=0;i????????b[i]=a[i];
????for（i=0;i<32-n;i++）
????????a[i]=a[i+n];
????for（i=32-n;i<32;i++）
????	a[i]=b[i-32+n];
}

int?turn（int?nint?a[]int?b）?//將十進制轉化為其它數制
{
????int?i=0temp;
????do{
????????temp=n%b;
????????a[i++]=temp;
????}while（n=n/b）;
	return?i;
}??

void?trans（char?a[]int?c[]）????//實現十六進制轉化為二進制
{
	int?ijflag;
	int?b[16][4]={{0000}{0001}{0010}{0011}{0100}{0101}
	{0110}{0111}{1000}{1001}{1010}{1011}{1100}
	{1101}{1110}{1111}};
	for（i=0;i<8;i++）
	{
		switch（a[i]）
		{
		case?‘0‘:
			flag=0;break;
		case?‘1‘?:?
			flag=1;break;
		case?‘2‘?:
			flag=2;break;
		case?‘3‘?:?
			flag=3;break;
		case?‘4‘?:?
			flag=4;break;
		case?‘5‘?:?
			flag=5;break;
		case?‘6‘?:?
			flag=6;break;
		case?‘7‘?:
			flag=7;break;
		case?‘8‘?:?
			flag=8;break;
		case?‘9‘?:?
			flag=9;break;
		case?‘a‘?:
			flag=10;break;
		case?‘b‘?:?
			flag=11;break;
		case?‘c‘?:?
			flag=12;break;
		case?‘d‘?:?
			flag=13;break;
		case?‘e‘?:
			flag=14;break;
		case?‘f‘?:?
			flag=15;break;
		default:?break;
		}
		for（j=0;j<4;j++）
			c[4*i+j]=b[flag][j];
	}
}
void?w（char?p[]int?w[][32]）?????//將輸入的字符串化為二進制并分組
{
	int?ijflagnle=0k=0;
	int?b[512]s[64];
????for（i=0;p[i];i++）????//將字符串化為二進制
	{???
???????unsigned??int?j=0x80tmp=*（p+i）;???
???????for（;j;j>>=1）
		???if（j&tmp）?b[k++]=1;???
???????????else???b[k++]=0;???
	}??
	flag=k;??????????//flag為輸入字符串的位數
????????b[k++]=1;????????//填充一個1其余位補0
	for（;k<512;k++）	b[k]=0;
????????n=turn（flags2）;
????????for（l=511;l>511-n;l--）??//將長度添加到數據塊
????????????b[l]=s[e++];??
	l=0;
????for（i=0;i<16;i++）??????//將512個字分為16（*32）組
		for（j=0;j<32;j++）
		{
????????????w[i][j]=b[l++];
		}
????for（;i<80;i++）
????{?
		for（j=0;j<32;j++）
			w[i][j]=w[i-3][j]^w[i-8][j]^w[i-14][j]^w[i-16][j];
????????rotl（w[i]1）;
????}
}
void?f1（int?tint?B[]int?C[]int?D[]int?f[]）?//實現四個函數
{
	int?i;
	for（i=0;i<32;i++）
	{
		if（t>=0&&t<=19）?
			???f[i]=（B[i

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????467??2009-12-21?18:12??sha\200702054029譚金林\說明.txt

?????文件?????163905??2009-11-22?23:37??sha\200702054029譚金林\fSHA_1.exe

?????文件?????172098??2009-11-29?20:24??sha\200702054029譚金林\SHA_1.exe

?????文件???????6261??2009-11-29?20:24??sha\200702054029譚金林\SHA_1.cpp

?????文件?????238592??2009-12-21?19:07??sha\200702054029譚金林\sha_1.doc

?????文件?????288768??2009-12-22?20:45??sha\200702054029譚金林\sha-1.doc

?????文件????????467??2009-12-03?11:02??sha\SHA_1算法\說明.txt

?????文件?????163905??2009-11-22?23:37??sha\SHA_1算法\fSHA_1.exe

?????文件?????172098??2009-11-29?20:24??sha\SHA_1算法\SHA_1.exe

?????文件?????236032??2009-12-21?17:34??sha\SHA_1算法\sha_1.doc

?????目錄??????????0??2009-11-29?20:09??sha\200702054029譚金林

?????目錄??????????0??2009-12-21?17:35??sha\SHA_1算法

?????目錄??????????0??2009-11-22?12:38??sha

-----------?---------??----------?-----??----

??????????????1442593????????????????????13