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  • 大小: 6KB
    文件類型: .rar
    金幣: 2
    下載: 0 次
    發布日期: 2021-06-09
  • 語言: C/C++
  • 標簽: RSA??信息安全??

資源簡介

這是一個完整的rsa算法 包括多種功能,包括對文件的加密解密以及簡單的數據測試

資源截圖

代碼片段和文件信息

#include
#include
#include????
#include???
#include?
#include?
#define?MAX?100
#define?LEN?sizeof(struct?slink)
void?sub(int?a[MAX]int?b[MAX]?int?c[MAX]?);

struct?slink
{?
int??bignum[MAX];
/*bignum[98]用來標記正負號,1正,0負bignum[99]來標記實際長度*/
????struct?slink?*next;
};

/*/--------------------------------------自己建立的大數運算庫-------------------------------------*/

void??print(??int?a[MAX]?)
???{
???int?i;
???for(i=0;i ???printf(“%d“a[a[99]-i-1]);
???printf(“\n\n“);
???return;
???}


int??cmp(int?a1[MAX]int?a2[MAX])
{???int?l1?l2;
int?i;
l1=a1[99];
l2=a2[99];
if?(l1>l2)
?????return?1;
????if?(l1???????return?-1;
????for(i=(l1-1);i>=0;i--)
???{
???if?(a1[i]>a2[i])
???return?1?;
???if?(a1[i] ???return?-1;
???}
????return?0;
}

void?mov(int?a[MAX]int?*b)
{
int?j;
for(j=0;j b[j]=a[j];

return?;
}


void?mul(int?a1[MAX]int?a2[MAX]int?*c)
{
?int?ij;
?int?y;
?int?x;
?int?z;
?int?w;
?int?l1?l2;
l1=a1[MAX-1];
l2=a2[MAX-1];
if?(a1[MAX-2]==‘-‘&&?a2[MAX-2]==‘-‘)
c[MAX-2]=0;
else?if?(a1[MAX-2]==‘-‘)
c[MAX-2]=‘-‘;
else?if?(a2[MAX-2]==‘-‘)
c[MAX-2]=‘-‘;
?for(i=0;i?{
??for(j=0;j??{
?????x=a1[i]*a2[j];
?????y=x/10;
?????z=x%10;
?????w=i+j;
?????c[w]=c[w]+z;
?????c[w+1]=c[w+1]+y+c[w]/10;
?????c[w]=c[w]%10;
??}
?}
?w=l1+l2;
?if(c[w-1]==0)w=w-1;
?c[MAX-1]=w;
?return;
}?

void?add(int?a1[MAX]int?a2[MAX]int?*c)
{

?int?il1l2;
?int?lentemp[MAX];
?int?k=0;
l1=a1[MAX-1];
l2=a2[MAX-1];
if((a1[MAX-2]==‘-‘)&&(a2[MAX-2]==‘-‘))
{
c[MAX-2]=‘-‘;
}
else?if?(a1[MAX-2]==‘-‘)
{
mov(a1temp);
temp[MAX-2]=0;
sub(a2tempc);
return;
}
else?if?(a2[MAX-2]==‘-‘)
{
mov(a2temp);
temp[98]=0;
sub(a1tempc);
return;
}

if(l1?else?len=l2;
?for(i=0;i?{
??c[i]=(a1[i]+a2[i]+k)%10;
??k=(a1[i]+a2[i]+k)/10;
?}
?if(l1>len)
?{
??for(i=len;i??{
???c[i]=(a1[i]+k)%10;
??????k=(a1[i]+k)/10;???
??}
??if(k!=0)
??{
???c[l1]=k;
???len=l1+1;
??}
??else?len=l1;
?}
?else
?{
??for(i=len;i??{
???c[i]=(a2[i]+k)%10;
???k=(a2[i]+k)/10;???
??}
??if(k!=0)
??{
???c[l2]=k;
???len=l2+1;
??}
??else?len=l2;
?}
??c[99]=len;
??return;
}?


void?sub(int?a1[MAX]int?a2[MAX]int?*c)
{
?int?il1l2;
?int?lent1[MAX]t2[MAX];
?int?k=0;
l1=a1[MAX-1];
l2=a2[MAX-1];
if?((a1[MAX-2]==‘-‘)?&&?(a2[MAX-2]==‘-‘))
{
mov(a1t1);
????????mov(a2t2);
t1[MAX-2]=0;
????????t2[MAX-2]=0;
sub(t2t1c);
return;
}
else?if(?a2[MAX-2]==‘-‘)
{
mov(a2t2);
t2[MAX-2]=0;
add(a1t2c);
return;
}
else?if?(a1[MAX-2]==‘-‘)
{
mov(a2t2);
t2[MAX-2]=‘-‘;
add(a1t2c);
return;
}

?if(cmp(a1a2)==1)
?{
?
?len=l2;
?for(i=0;i?{
?if?((a1[i]-k-a2[i])<0)
?{
?c[i]=(a1[i]-a2[i]-k+10)%10;
?????k=1;
?}
?????else?
?{
?c[i]=(a1[i]-a2[i]-k)%10;
?????k

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件??????22646??2010-11-20?17:58??RSA算法完整版.cpp

-----------?---------??----------?-----??----

????????????????22646????????????????????1


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