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資源簡介

PL0符號表輸出及分析，幾乎每行帶注釋，下載之后即可看見.h和.c文件，可直接編譯運行（如dev-c++、vs）

資源截圖

代碼片段和文件信息 

/*
?*?PL/0?complier?program?for?win32?platform?（implemented?in?C）
?*
?*?The?program?has?been?test?on?Visual?C++?6.0?Visual?C++.NET?and
?*?Visual?C++.NET?2003?on?Win98?WinNT?Win2000?WinXP?and?Win2003
?*
?*?使用方法：
?*?運行后輸入PL/0源程序文件?
?*/

#include?
#include?
#include?“pl0_Nametable.h“
#include?“string.h“

//?分割符，0表示0個‘--‘，1表示1個，以此類推
int?Tree_level[500];
//?存單詞
char*?Tree[500];?
//?數單個個數
int?word_num?=?0;

void?Gen_grammerTree（）{
	int?i=0;?
	printf（“\nGrammer?Tree\n“）;
????for（i=0?;?i????????switch?（Tree_level[i]）
	????{
		????case?0:
		????	printf（“%s\n“Tree[i]）;
		????????break;
		????case?1:
		????	printf（“--%s\n“Tree[i]）;
		????????break;
		????case?2:
		????????printf（“----%s\n“Tree[i]）;
		????????break;
		????case?3:
		????????printf（“------%s\n“Tree[i]）;
		????????break;
		????case?4:
		????????printf（“--------%s\n“Tree[i]）;
		????????break;
		????case?5:
		????????printf（“----------%s\n“Tree[i]）;
		????????break;
		????case?6:
		????????printf（“------------%s\n“Tree[i]）;
		????????break;
		????case?7:
		????????printf（“--------------%s\n“Tree[i]）;
		????????break;
		????case?8:
		????????printf（“----------------%s\n“Tree[i]）;
		????????break;
		????case?9:
		????????printf（“------------------%s\n“Tree[i]）;
		????????break;
		????case?10:
		????????printf（“--------------------%s\n“Tree[i]）;
		????????break;
		????case?11:
		????????printf（“----------------------%s\n“Tree[i]）;
		????????break;
		????case?12:
		????????printf（“------------------------%s\n“Tree[i]）;
		????????break;
		????case?13:
		????????printf（“--------------------------%s\n“Tree[i]）;
		????????break;
		????case?14:
		????????printf（“----------------------------%s\n“Tree[i]）;
		????????break;
		????case?15:
		????????printf（“------------------------------%s\n“Tree[i]）;
		????????break;
		????case?16:
		????????printf（“--------------------------------%s\n“Tree[i]）;
		????????break;
????????????case?17:
????????????????printf（“----------------------------------%s\n“Tree[i]）;
????????????????break;
????????????case?18:
????????????????printf（“------------------------------------%s\n“Tree[i]）;
????????????????break;
????????????case?19:
????????????????printf（“--------------------------------------%s\n“Tree[i]）;
????????????????break;
????????????case?20:
????????????????printf（“----------------------------------------%s\n“Tree[i]）;
????????????????break;
????????????case?21:
????????????????printf（“------------------------------------------%s\n“Tree[i]）;
????????????????break;
????????????case?22:
????????????????printf（“--------------------------------------------%s\n“Tree[i]）;
????????????????break;
????????????case?23:
????????????????printf（“----------------------------------------------%s\n“Tree[i]）;
????????????????break;
????????????case?24:
????????????????printf（“--------------------------------------------

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????50323??2020-04-12?16:25??pl0_Nametable_ANSI.c
?????文件????????6352??2020-04-05?23:03??pl0_Nametable.h

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