-
大小: 928KB文件類型: .rar金幣: 2下載: 0 次發(fā)布日期: 2024-01-28
- 語言: C/C++
- 標簽:
資源簡介
二分法求解;.牛頓法求解;高斯消去法求解;雅可比迭代法求解;拉格朗日插值;牛頓插值;最小二乘法擬合;龍貝格方法計算積分;歐拉方法求解初值問題;

代碼片段和文件信息
#include?
#include?
#include?
using?namespace?std;
void?twoFF()
{cout<<“所求方程為x*x*x-x*x-2*x+1=0\n“;
double?ab;
cout<<“請輸入求根區(qū)間:\n“;
cout<<“a=“;
cin>>a;
cout<<“b=“;
cin>>b;
double?cd;
cout<<“請輸入要求達到的精度:\n“;
cout<<“精度為“;
cin>>d;
cout<<“a=0\n“;
cout<<“b=1\n“;
int?n=0;
while(c>d?||?c<-d)
{if((a*a*a-a*a-2*a+1)*((a+b)*(a+b)*(a+b)/8-(a+b)*(a+b)/4-a-b+1)>0){a=(a+b)/2;cout<<“a=“<else?{b=(a+b)/2;cout<<“b=“<n++;
c=a-b;}
cout<<“迭代次數(shù)為“< }
void?Newton()
{cout<<“求方程x*(x+1)*(x+1)-1=0在x=0.4附近的根\n“;
double?x=0.4m;
double?cd;
cout<<“請輸入要求達到的精度:\n“;
cout<<“精度為“;
cin>>d;
cout<<“x=0.4\n“;
int?n=0;
while(c>d?||?c<-d){m=x;
x?=?x?-(x*(x+1)*(x+1)-1)?/(3*x*x+4*x+1);
cout<<“x=“< c=m-x;
n++;}
cout<<“迭代次數(shù)為“< }
int?n;
double?a[100][101];
double?m[100];
void?changerow(int?g)
{int?ij;
if(a[g-1][g-1]==0)
{int?k;
for(k=g;k {if(a[k][g-1]!=0)break;
}
for(j=0;j {m[j]=a[g-1][j];
a[g-1][j]=a[k][j];
a[k][j]=m[j];}
}
for(i=g;i m[i]=a[i][g-1]/a[g-1][g-1];
for(i=g;i for(j=g-1;j a[i][j]=a[i][j]-m[i]*a[g-1][j];
for(i=0;i {cout<<“\n“;
for(j=0;j ????printf(“????%2f“a[i][j]);
????}
cout<<“\n“;
}
void?GSXU()
{
printf(“輸入方程個數(shù):“);
cin>>n;
printf(“按行輸入各個方程的系數(shù):\n“);
int?ij;
for(i=0;i for(j=0;j cin>>a[i][j];
for(i=0;i {cout<<“\n“;
for(j=0;j ????printf(“????%2f“a[i][j]);}
cout<<“\n“;
for(i=1;i {changerow(i);}
double?x[100];
int?r=n-1;
x[n-1]=a[n-1][n]/a[n-1][n-1];
double?p=0q;
for(i=n-2;i>=0;i--)
{
for(j=n-1;j>=r;j--)
{q=a[i][j]*x[j];
p=p+q;
}
x[i]=(a[i][n]-p)/a[i][i];
r--;
p=0;}
printf(“方程組解為“);
cout<<“X=“<<“(“;
for(i=0;i cout< cout< cout<<“)“< }
void?Jacobi()
{double?a[4][4]?x1[100]x2[100]x3[100];
x1[0]=0;x2[0]=0;x3[0]=0;
printf(“按行輸入三元方程的各個系數(shù):\n“);
int?ij;
for(i=0;i<3;i++)
for(j=0;j<4;j++)
cin>>a[i][j];
x1[1]=a[0][3]/a[0][0];
x2[1]=a[1][3]/a[1][1];
x3[1]=a[2][3]/a[2][2];
double?c=1;
for(i=1;c>0.000001;i++)
{
x1[i]=x1[1]-a[0][1]/a[0][0]*x2[i-1]-a[0][2]/a[0][0]*x3[i-1];
x2[i]=x2[1]-a[1][0]/a[1][1]*x1[i-1]-a[1][2]/a[1][1]*x3[i-1];
x3[i]=x3[1]-a[2][0]/a[2][2]*x1[i-1]-a[2][1]/a[2][2]*x2[i-1];
c=fabs(x1[i]-x1[i-1])+fabs(x2[i]-x2[i-1])+fabs(x3[i]-x3[i-1]);
cout<}
}
double?x[100]y[100];
void?input(int?n)
{
int?i;
for(i=0;i {cout<<“x[“<scanf(“%lf“&x[i]);
cout<<“y[“<scanf(“%lf“&y[i]);}
}
void?Lagrange()
{
int?m;
printf(“輸入點的個數(shù):\n“);
scanf(“%d“&m);
double?v;
printf(“輸入所求X的值:\n“);
scanf(“%lf“&v);
input(m);
int?ij;
double?ab=1cd=1ef=1gh=1pq=0;
for(i=0;i {??for(j=0;j???{a=x[i]-x[j];
????b=b*a;
c=v-x[j];
d=d*c;}
???for(j=i+1;j ???{e=x[i]-x[j];
????f=f*e;
g=v-x[j];
h=h*g;}
p=d*h*y[i]/b/f;
cout<<“L“<
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????6710??2007-01-14?19:57??常用數(shù)值計算方法c++源代碼實現(xiàn)\wyl.cpp
?????文件???????3723??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\wyl.dsp
?????文件??????74752??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\Debug\vc60.idb
?????文件?????110592??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\Debug\vc60.pdb
?????文件????2079664??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\Debug\wyl.pch
?????文件?????306473??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\Debug\wyl.obj
?????文件?????831928??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\Debug\wyl.ilk
?????文件?????589938??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\Debug\wyl.exe
?????文件????1131520??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\Debug\wyl.pdb
?????文件??????33792??2011-10-11?09:21??常用數(shù)值計算方法c++源代碼實現(xiàn)\wyl.ncb
?????文件???????1165??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\wyl.plg
?????文件??????48640??2011-10-11?09:21??常用數(shù)值計算方法c++源代碼實現(xiàn)\wyl.opt
?????文件????????531??2011-10-11?09:21??常用數(shù)值計算方法c++源代碼實現(xiàn)\wyl.dsw
?????目錄??????????0??2011-10-11?09:19??常用數(shù)值計算方法c++源代碼實現(xiàn)\Debug
?????目錄??????????0??2011-10-11?09:18??常用數(shù)值計算方法c++源代碼實現(xiàn)
-----------?---------??----------?-----??----
??????????????5219428????????????????????15
評論
共有 條評論