import?java.io.*;

class?KeywordIdentifier?{
????public?static?void?main（String[]?args）?throws?Exception?{
????????char[]?kc?=?new?char[800];????????????????//保存關(guān)鍵字集的字符
????????String[]?kw?=?new?String[55];??????????????//保存關(guān)鍵字
????????int?kcountkj=0;	???????????????????????//kj是關(guān)鍵字?jǐn)?shù)量-1

????????char[]?s?=?new?char[10000];
????????String[]s1?=?new?String[1000];
????????int?countj=1;
????????BufferedReader?br?=?new?BufferedReader（new?FileReader（“第二題測試java源程序.java“））;????//打開java源文件
????????count?=?br.read（s）;
????????
????????String[]?f1?=?new?String[5];?????//輔助識(shí)別
????????char[]?sk?=?new?char[2];
????????
????????int?imnk1=0k2=0;
????????int?num[]?=?new?int[55];???????????????????//統(tǒng)計(jì)對(duì)應(yīng)字符出現(xiàn)的次數(shù)	
//讀入關(guān)鍵字集???????
????????BufferedReader?kbr?=?new?BufferedReader（new?FileReader（“關(guān)鍵字集.txt“））;??//讀關(guān)鍵字文本文件流?????
????????kcount?=?kbr.read（kc）;????????????????????????//kcount表示從文件里面讀出字符個(gè)數(shù)。
????????for?（i?=?0;?i?????????	kw[i]=““;
????????for?（i?=?0;?i?????????	if（kc[i]>=‘a(chǎn)‘?&&?kc[i]<=‘z‘）
????????????????kw[kj]+=kc[i];
????????????else?if（kc[i+1]>=‘a(chǎn)‘?&&?kc[i+1]<=‘z‘）{
????????????	kj++;
????????????????if（kw[kj-1]==kw[kj]）?kj--;}??????????//確保第一個(gè)單詞前面的空格不影響使s1[0]==“?“
????????}
????????char?c1=‘\0‘;
/*????????System.out.print（“Java語言中所有關(guān)鍵字：“+“\n“）;
????????for（i=0;i<=kj;i++）??????????????????????????????//輸出測試用的文本信息
????????????System.out.print（kw[i]+“\t“）;
????????System.out.print（“\n“）;*/

//我們有所有的關(guān)鍵字，現(xiàn)在要找出源程序中除去注釋之后的關(guān)鍵字
????????for?（i?=?0;?i?????????	num[i]?=?0;
????????for?（i?=?0;?i?????????????s1[i]=““;
????
????????f1[0]=“//“;?f1[1]=“/*“;?f1[2]=“*/“;?f1[3]=“/**“;????//輔助判斷
????????f1[4]=““;
????????sk[0]=‘\n‘;?
????????f1[4]+=sk[0];
????????
????????if（（s[0]>=‘a(chǎn)‘?&&?s[0]<=‘z‘）?||?（s[0]==‘/‘）?||?（s[0]==‘*‘））
????????????s1[1]+=s[0];
????????for?（i?=?1;?i?<=?count;?i++）{??????????//關(guān)鍵字肯定是小寫，所以只讀小寫單詞和注釋，換行符

????????	if（（s[i]>=‘a(chǎn)‘?&&?s[i]<=‘z‘）?||?（s[i]==‘/‘）?||?（s[i]==‘*‘））{?????	????
????????		if（（s[i]==‘/‘）?||?（s[i]==‘*‘））{
????????			if（s[i-1]>=‘a(chǎn)‘?&&?s[i-1]<=‘z‘）???????				
????????				j++;
????????			s1[j]+=s[i];
????????			if（s1[j].equals（f1[0]））{
????????????????		for（n=i+1;k1==0?&&?n?<=?count;n++）{
???????????????