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Java 從數據流中讀取XML(提高篇-實例358).zip
代碼片段和文件信息
/**
?*?@jdk版本:1.6
?*?@編碼時間:2010-3-20
?*/
package?com.mingrisoft.SAX_demo;
import?java.io.File;
import?java.io.FileInputStream;
import?java.io.FileNotFoundException;
import?java.io.IOException;
import?java.io.InputStream;
import?javax.xml.parsers.ParserConfigurationException;
import?javax.xml.parsers.SAXParser;
import?javax.xml.parsers.SAXParserFactory;
import?org.xml.sax.SAXException;
import?org.xml.sax.helpers.DefaultHandler;
/**
?*?@author?bwm
?*?
?*/
public?class?ParserInputStream?{
/**
?*?從數據流讀取xml
?*?
?*?@param?inputStream
?*????????????數據流
?*/
public?void?parseInputStream(InputStream?inputStream)?{
SAXParser?parser;
SAXParserFactory?factory?=?SAXParserFactory.newInstance();
try?{
parser?=?factory.newSAXParser();
parser.parse
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件?????????232??2010-12-17?09:48??.classpath
?????文件?????????379??2010-12-17?16:10??.project
?????文件?????????635??2010-12-17?14:43??.settings\org.eclipse.jdt.core.prefs
?????文件????????1977??2011-02-14?10:45??bin\com\mingrisoft\SAX_demo\ParserInputStream.class
?????文件????????1661??2010-12-17?16:19??src\com\mingrisoft\SAX_demo\ParserInputStream.java
?????文件????????1030??2010-12-16?17:11??xm
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