資源簡介
采用本地脈沖信號對跳時ppm系統進行解調
代碼片段和文件信息
%%%?本程序在不考慮多徑的情況下,并已知同步時采用干凈的本地脈沖信號對跳時ppm系統進行解調?%%%
clear?all
Ts=0.4*10^(-9);%the?bandwidth?is?1/(2*Ts)=2.5*10^9;
%------------------------------
Tbit=16*10^(-9);%the?peiod?of?bit;
fbit=1/Tbit;%speed?of?transmitted;
%---------------------------------
Tsample=Tbit/10;%the?sampling?frequency;
fsample=1/Tsample;%frequency?of?sampling;
%------------------------------------
sampling_point=fsample/fbit;?%?the?number?of?sampling?point?in?a?bit
n=-(sampling_point/2)+1:sampling_point/2;?%sampling?point
fc=2.5*10^9;%脈沖譜的中心頻率
e=exp(1);
t_delay=10;%ppm調制時的時延;
Nf=2;%一個符號用Nf個幀表示;
N=10;M=195;MM=10000;
Ebn0=[-2:2:12];
point_num=2*M+sampling_point;
%信號的行式:
a=0.2;
Tc=0.2;
n=0:0.04:0.36;
s=(1-4*pi*((n-Tc)/a).^2).*exp(-2*pi*((n-Tc)/a).^2);
R=3;
s1=[zeros(1t_delay)?s];
zero_serio=zeros(12*M);
zero_serio1=zeros(12*M-t_delay);
zero_serio2=zeros(1t_delay);
ss=[s?zero_serio];
sss=[s1?zero_serio1];
zero1=zeros(1M);
matching_sig=[zero1?s?zero1];
ss_rep0=repmat(ss1Nf);
ss_rep1=repmat(sss1Nf);
power=((norm(ss))^2)/point_num;%一個脈沖的能量;?
%?產生一本地信號;
local_sig1=[s?(-1)*s?zeros(1point_num-2*sampling_point)];%1*400;
PN_code0=[0111011000111110011010010000101];
PN_code1=[14292722122417371531302825196132620918481612510211123];
%計算誤碼率;
j=1;
ebn0_num=0;
for?num=1:2:15
????ebn0_num=ebn0_num+1;
????ebn0=num-3;
????sita=sqrt((power*point_num*0.5)/(10^(ebn0/10)));
????for?calculate_num=1:MM
????????%產生信源?
????????source_date=randint(1N);
????????%進行ppm調制
????????date_modulated=[];local_sig=[];
????????for?i=1:N
????????????if?source_date(i)==1?
????????????????date_modulated1=ss_rep1;
????????????else
????????????????date_modulated1=ss_rep0;
????????????end?
????????????g1=zeros(1point_num);
????????????g2=zeros(1point_num);
????????????b1=zeros(1point_num);
????????????b2=zeros(1point_num);
????????????if?(j>0)&(j<31)?
????????????????for?z=1:20
????????????????????g1(PN_code1(j)*10+z)=date_modulated1(z);
????????????????????g2(PN_code1(j+1)*10+z)=date_modulated1(point_num+z);
????????????????end
????????????????for?z=1:2*sampling_point
????????????????????b1(PN_code1(j)*10+z)=local_sig1(z);
????????????????????b2(
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