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資源簡介

擴頻通信系統,DSSS直接序列擴頻通信系統仿真Matlab程序。Matlab2008驗證可用,參數可調。

資源截圖

代碼片段和文件信息

clear?x;
x=demodz;

clear?prob0;
clear?prob1;
prob0=zeros(1lieH);
prob1=zeros(1lieH);

for?a=1:lieH
????prob1(1a)=1/(1+exp(x(1a)*2/sigma^2));
????prob0(1a)=1-prob1(1a);
end

q0=zeros(hangHlieH);
q1=zeros(hangHlieH);
r0=zeros(hangHlieH);
r1=zeros(hangHlieH);

for?i=1:lieH
????for?jo=1:liezhong
????????q0(ncol(joi)i)=prob0(1i);
????????q1(ncol(joi)i)=prob1(1i);
????end
end




for?lp=1:20
????for?i=1:hangH
????????for?jo=1:hangzhong
????????????delta=1;
????????????for?l=1:hangzhong
????????????????if?l~=jo
????????????????????delta=delta*(1-2*q1(inrow(il)));
????????????????end
????????????end
????????????r0(inrow(ijo))=0.5+0.5*delta;
????????????r1(inrow(ijo))=1-r0(inrow(ijo));
????????end
????end

????for?i=1:lieH
????????for?jo=1:liezhong
????????????alpha1=1;
????????????alpha2=1;
????????????alpha3=1;
????????????alpha4=1;
????????????for?l=1:liezhong
????????????????if?l~=jo
????????????????????alpha1=alpha1*r0(ncol(li)i);
????????????????????alpha2=alpha2*r1(ncol(li)i);
????????????????end
????????????end
????????????%---------------------------------------------------
????????????if?(prob0(1i)*alpha1+prob1(1i)*alpha2)==0
????????????????alpha3=1;
????????????else?alpha3=1/(prob0(1i)*alpha1+prob1(1i)*alpha2);
????????????end
????????????%----------------------------------------------------
????????????q0(ncol(joi)i)=alpha3*prob0(1i)*alpha1;
????????????q1(ncol(joi)i)=alpha3*prob1(1i)*alpha2;
????????end
????end

????
????Q0=zeros(1lieH);
????Q1=zeros(1lieH);
????for?i=1:lieH
????????delta1=1;
????????delta2=1;
????????for?jo=1:3
????????????delta1=delta1*r0(ncol(joi)i);
????????????delta2=delta2*r1(ncol(joi)i);
????????end
????????if?(prob0(1i)*delta1+prob1(1i)*delta2)==0
????????????delta3=1;
????????else?delta3=1/(prob0(1i)*delta1+prob1(1i)*delta2);
????????end
????????Q0(1i)=delta3*prob0(1i)*delta1;
????end
????
????decoded=zeros(1lieH);
????for?i=1:lieH
????????if?Q0(1i)<0.5
????????????decoded(1i)=1;
????????end
????end
????
????clear?check;
????check=H*decoded‘;
????biaozhi=0;
????
????for?i=1:hangH
????????if?mod(check(i1)2)==1
????????????biaozhi=1;
????????????break;
????????end
????end
????
????if?biaozhi==0
????????break;
????end
end


?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2015-04-02?21:31??Dsss\
?????文件????????2168??2009-06-16?09:49??Dsss\after_decode_out.mat
?????目錄???????????0??2015-04-03?19:48??__MACOSX\
?????目錄???????????0??2015-04-03?19:48??__MACOSX\Dsss\
?????文件?????????212??2009-06-16?09:49??__MACOSX\Dsss\._after_decode_out.mat
?????文件????????2167??2009-06-16?09:49??Dsss\before_decode_out.mat
?????文件?????????212??2009-06-16?09:49??__MACOSX\Dsss\._before_decode_out.mat
?????文件???????70064??2015-04-02?19:45??Dsss\carrier_demod_out.mat
?????文件?????????212??2015-04-02?19:45??__MACOSX\Dsss\._carrier_demod_out.mat
?????文件????????2350??2008-06-26?11:08??Dsss\decode.m
?????文件?????????212??2008-06-26?11:08??__MACOSX\Dsss\._decode.m
?????文件????????8103??2009-06-13?23:26??Dsss\digtal_signal_source.mat
?????文件?????????212??2009-06-13?23:26??__MACOSX\Dsss\._digtal_signal_source.mat
?????文件??????998164??2009-06-14?17:02??Dsss\dsss.mdl
?????文件?????????212??2009-06-14?17:02??__MACOSX\Dsss\._dsss.mdl
?????文件????????1098??2007-04-22?14:07??Dsss\encode.m
?????文件?????????212??2007-04-22?14:07??__MACOSX\Dsss\._encode.m
?????文件???????12259??2009-06-13?23:31??Dsss\encode_in.mat
?????文件?????????212??2009-06-13?23:31??__MACOSX\Dsss\._encode_in.mat
?????文件????????3271??2009-06-14?15:21??Dsss\encode_out.mat
?????文件?????????212??2009-06-14?15:21??__MACOSX\Dsss\._encode_out.mat
?????文件????????1182??2009-06-16?09:49??Dsss\main_decode.m
?????文件?????????212??2009-06-16?09:49??__MACOSX\Dsss\._main_decode.m
?????文件?????????356??2009-06-14?21:10??Dsss\main_encode.m
?????文件?????????212??2009-06-14?21:10??__MACOSX\Dsss\._main_encode.m

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