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  • 大小: 5KB
    文件類型: .m
    金幣: 1
    下載: 0 次
    發布日期: 2021-05-23
  • 語言: Matlab
  • 標簽: 基于??MATLAB??模糊??

資源簡介

基于MATLAB的模糊控制表計算程序.m

資源截圖

代碼片段和文件信息

clc;
clear;tic
E?=?[10.80.70.40.100000000;
????0.20.710.70.300000000;
????00.10.30.710.70.2000000;
????00000.10.61000000;
????00000010.60.10000;
????0000000.20.710.70.30.10;
????000000000.20.710.70.3;
????000000000.10.40.70.81]%%8*13
EC?=[10.70.30000000000;
????0.30.710.70.300000000;
????000.30.710.70.3000000;
????00000.30.710.70.30000;
????0000000.30.710.70.300;
????000000000.30.710.70.3;
????00000000000.30.71]%%7*13
U=[10.70.30000000000;
????0.30.710.70.300000000;
????000.30.710.70.3000000;
????00000.30.710.70.30000;
????0000000.30.710.70.300;
????000000000.30.710.70.3;
????00000000000.30.71]%%7*13
rulelist=??[1111244;
????????????1111244;
????????????2222455;
????????????2234566;
????????????2234566;
????????????3346666;
????????????4467777;
????????????4467777]%%8*7

for?iii=1:13?????????????%偏差E的模糊值控制????????
????for?jjj=1:13?????????%偏差率EC的模糊值控制????????
????????for?ii=1:8???????%偏差E的模糊規則控制????
????????????for?jj=1:7???%偏差變化率EC的模糊規則控制
????????????????A_rulelist?=?rulelist(iijj);?%查模糊規則表
????????????????%******計算C1A‘************
????????????????A?=?E(ii:);??????%取A‘????
????????????????C_A?=?U(A_rulelist:);?????%取Ci?????
????????????????for?i=1:13?????%求R1A
????????????????????for?j=1:13
????????????????????????if(A(i)?>?C_A(1j))
????????????????????????????Ra(ij)?=?C_A(1j);
????????????????????????else?
????????????????????????????Ra(ij)?=?A(i);
????????????????????????end
????????????????????end
????????????????end

????????????????AA?=?zeros(113);?%取AA=A‘?
????????????????%AA(1iii)?=?E(iiiii);???????
????????????????AA(1iii)?=?1;
???????????????????????????????
????????????????for?i=1:13??????%先取小
????????????????????for?j=1:13??
????????????????????????if(AA(j)?>?Ra(ji))
?????????????????????????????A_qux(ji)?=?Ra(ji);
????????????????????????else
?????????????????????????????A_qux(ji)?=?AA(j);
????????????????????????end
????????????????????end
????????????????end

????????????????for?i=1:13?????%再取大,,,求和CiA
????????????????????max?=?A_qux(1i);
????????????????????for?j=1:13
????????????????????????if(max?????????????????????????????max?=?A_qux(ji);
??????

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