clear;
clc;
directory=uigetdir（‘‘‘親，請選擇測試圖片路徑‘）;
ImageNum=10000;
numis=textread（‘test.txt‘‘%1d‘）;??%numis?是正確的ImageNum個樣本值
fid=fopen（‘log.txt‘‘w‘）;
%讀出77和66的特征值
fea66=load（‘features6.txt‘）;
fea77=load（‘features7.txt‘）;
estat=zeros（110）;
h_w=waitbar（0‘請稍后，正在處理中>>>>>>>>‘）;
for?i=1:ImageNum
????featone=zeros（112）;?????%統(tǒng)計特征
????%讀取圖像并二值化
????impath=fullfile（directory[‘TestImage_‘?num2str（i‘%05d‘）?‘.bmp‘]）;
????rawim=imread（impath）;
????xx=find（rawim<155）;
????rawim（xx）=0;
????x=find（rawim>=155）;
????rawim（x）=255;
????bwim=im2bw（rawim0.5）;%二值化
????
????%讀出來的這個數(shù)真實(shí)值是多少？jud?保存之
????jud=numis（i）;
????if?jud==0???????%如果是0，放在第十個
????????jud=10;
????end
????%%%%%%%%%%%%%%%?特?征?一?%%%%%%%%%%%%%%%%%
????%提取特征---6+6個分割線上連續(xù)點(diǎn)個數(shù)
????old=1;????????%表示上一個點(diǎn)值
????new=1;????????%表示現(xiàn)在這個點(diǎn)的值
????count=0;??????%記錄發(fā)生了多少次變化
????for?c=1:6???????????%提取橫向特征
????????xl=4*c;
????????for?d=1:28??????%遍歷縱向的28個點(diǎn)
????????????old=new;
????????????new=bwim（dxl）;
????????????if（old~=new）????????%如果發(fā)生顏色變化則記錄
????????????????count=count+1;
????????????end
????????end
????????featone（c）=featone（c）+count/2;??%第jud個數(shù)第c個特征
????????count=0;
????end
????for?c=1:6???????????%提取縱向特征????
????????yl=4*c;
????????for?d=1:28
????????????old=new;
????????????new=bwim（yld）;
????????????if（old~=new）
????????????????count=count+1;
????????????end
????????end
????????featone（c+6）=featone（c+6）+count/2;
????????count=0;
????end
????%%%%%%%%%%%%%%%?特?征?二?%%%%%%%%%%%%%%%%%
????%讀取每個塊的像素個數(shù)
????gridnum=zeros（149）;????????%保存49個塊的黑色像素個數(shù)
????xbase=1;
????ybase=1;
????for?yz=0:6
????????for?xz=0:6??????????%這兩個是7*7的大塊
????????????for?ybase=1:4
????????????????for?xbase=1:4???????%這兩個是在4*4的小塊內(nèi)
????????????????????if（bwim（yz*4+ybasexz*4+xbase）==0）??%如果是黑色像素
????????????????????????gridnum（yz*7+xz+1）=gridnum（yz*7+xz+1）+1;
????????????????????end
????????????????end
????????????end
????????end
????end
????%歸一化特征二
????sum=0;
????for?c=1:49??????????
????????sum=sum+gridnum（c）;
????end
????numfea=zeros（149）;
????for?c=1:49
????????numfea（c）=gridnum（c）/sum;
????end
????%%%%%%%%%%%%?計算特征一的距離?%%%%%%%%%%%%%%%
????dist66=zeros（110）;?????????????%dist（c）?代表與標(biāo)準(zhǔn)第c個數(shù)字的距離
????for?c=1:10
????????for?d=1:12
????????????temp=featone（d）-fea66（cd）;????%該數(shù)字第d塊減去數(shù)字c第d塊特征值
????????????dist66（c）=dist66（c）+temp^2;
????????end
????end????
????%%%%%%%%%%%%?計算特征二的距離?%%%%%%%%%%%%%%%
????dist77=zeros（110）;?????????????%dist（c）?代表與標(biāo)準(zhǔn)第c個數(shù)字的距離
????for?c=1:10
????????for?d=1:49
????????????temp=numfea（d）-fea77（cd）;????%該數(shù)字第d塊減去數(shù)字c第d塊特征值
????????????dist77（c）=dist77（c）+temp^2;
????????end
????end
????%%%%%%%%%%?融合兩距離為一個距離?%%%%%%%%%%%%
????dist=zeros（110）;
????k2=240;
????for?c=1:10
????????dist=k2*dist77+dist66;
????end
????%計算最小距離和對應(yīng)的index
????[aindex]=min（dist）;
????if?index~=jud
????????if?jud==10
????????????temp=0;
????????else
????????????temp=jud;
????????end
????????if?index==10
????????????tempi=0;
????????e

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????487??2011-11-13?16:28??reame.txt

?????文件???????1320??2011-11-12?19:40??twofeatures?-?歸一化特征值\features6.txt

?????文件???????5400??2011-11-13?21:11??twofeatures?-?歸一化特征值\features7.txt

?????文件??????42000??2011-11-15?19:04??twofeatures?-?歸一化特征值\log.txt

?????文件????1072694??2011-11-15?19:05??twofeatures?-?歸一化特征值\ok.bmp

?????文件???????3271??2011-11-13?17:14??twofeatures?-?歸一化特征值\recognize.asv

?????文件???????3508??2011-11-15?19:03??twofeatures?-?歸一化特征值\recognize.m

?????文件??????20000??2011-11-10?21:32??twofeatures?-?歸一化特征值\test.txt

?????文件???????2578??2011-11-13?17:53??twofeatures?-?歸一化特征值\untitled.fig

?????文件???????4348??2011-11-13?17:53??twofeatures?-?歸一化特征值\untitled.png

?????文件???????3964??2011-11-14?09:19??twofeatures?-?歸一化特征值\untitled2.png

?????文件???????1451??2009-02-22?22:44??提取出?MNIST?內(nèi)容\Matlab_Read_t10k_images_idx3.m

?????文件???????1241??2009-02-22?22:42??提取出?MNIST?內(nèi)容\Matlab_Read_t10k_labels_idx1.m

?????文件???????1464??2009-02-22?22:44??提取出?MNIST?內(nèi)容\Matlab_Read_train_images_idx3.m

?????文件???????1250??2009-02-22?22:42??提取出?MNIST?內(nèi)容\Matlab_Read_train_labels_idx1.m

?????目錄??????????0??2011-11-15?19:05??twofeatures?-?歸一化特征值

?????目錄??????????0??2011-11-11?09:20??提取出?MNIST?內(nèi)容

-----------?---------??----------?-----??----

??????????????1164976????????????????????17