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  • 大小: 3KB
    文件類型: .m
    金幣: 1
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    發(fā)布日期: 2021-05-29
  • 語言: Matlab
  • 標(biāo)簽: 匹配濾波??

資源簡(jiǎn)介

matlab 線性調(diào)頻信號(hào)匹配濾波器 點(diǎn)目標(biāo)回波 距離分辨 提高性噪比

資源截圖

代碼片段和文件信息

%?input(‘\nPulse?radar?compression?processing:?\n?‘);
clear;
close?all;


????T=10e-6;????????????????????????????????????????%pulse?duration?10us
????B=30e6;?????????????????????????????????????????%chirp?frequency?modulation?bandwidth?30MHz
????Rmin=8500;Rmax=11500;??????????????????????????%range?bin
????R=[90001000010200];????????%position?of?ideal?point?targets
????%R=[12000?];
????RCS=[1?1?1??];??????????????????????????????%radar?cross?section
????%RCS=[1?];
%Parameter
C=3e8;??????????????????????????????????????????????%propagation?speed
K=B/T;??????????????????????????????????????????????%chirp?slope
Rwid=Rmax-Rmin;?????????????????????????????????????%receive?window?in?meter
Twid=2*Rwid/C;??????????????????????????????????????%receive?window?in?second
Fs=5*B;Ts=1/Fs;?????????????????????????????????????%sampling?frequency?and?sampling?spacing
Nwid=ceil(Twid/Ts);????????????????????????????????%receive?window?in?number

%Gnerate?the?echo??????
t=linspace(2*Rmin/C2*Rmax/CNwid);?????????????????%receive?window
??????????????????????????????????????????????????%open?window?when?t=2*Rmin/C
??????????????????????????????????????????????????%close?window?when?t=2*Rmax/C????????????????????????????
M=length(R);???????????????????????????????????????%number?of?targets????????????????????????????????????????
td=ones(M1)*t-2*R‘/C*ones(1Nwid);

SNR=[11010010000];

for?i=1:1:4
Srt1=RCS*(exp(1i*pi*K*td.^2).*(abs(td)n=sqrt(0.5*SNR(i))*(randn(size(Srt1))+1i*randn(size(Srt1)));
Srt=Srt1+n;

%Digtal?processing?of?pulse?compression?radar?using?FFT?and?IFFT
Nchirp=ceil(T/Ts);??????????????????????????????????%pulse?duration?in?number
Nfft=2^nextpow2(Nwid+Nwid-1

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