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    文件類型: .rar
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    發(fā)布日期: 2021-06-02
  • 語言: Matlab
  • 標簽: 數(shù)字全息??

資源簡介

N=512; A=zeros(N,N); B=zeros(N,N); for I=1:1:256 J=1:1:256 ImageNum=double(Image(I,J,1)); A(I,J)=ImageNum/255; B(I,J)=0; end end figure; imshow(A); pi=3.1415926; for I=1:1:N for J=1:1:N R=rand(1,1);%生成一個元素在0,1之間均勻分布的隨機矩陣R B(I,J)=A(I,J)*sin(R*2*pi);%平滑函數(shù)的傅里葉變換譜 A(I,J)=A(I,J)*cos(R*2*pi); F(I,J)=A(I,J)+j*B(I,J); end End%限制振幅的動態(tài)范圍,提高編碼的精度 F=fft2(F);%作二維快速傅里葉變換FFT Max=max(max(abs(F))); F=F/Max; A=real(F); B=imag(F); aIpha=0.5;%定義載波參數(shù)aIpha for I=1:1:N for J=1:1:N Xcos=(J-1)/127; A1(I,J)=cos(2*pi*aIpha*Xcos); B1(I,J)=sin(2*pi*aIpha*Xcos); end end%全息圖數(shù)據(jù)區(qū) for I=1:1:N for J=1:1:N HoIodata(I,J)=0.5+0.5*(A(I,J)*A1(I,J)+B(I,J)*B1(I,J)); end End M=512;N=512;%定義全息圖的大小 Hologram=zeros(M,M); S=M/N;%定義每個抽樣單元大小 for I=1:1:N for J=1:1:N Xa=(J-1)*S+1; Xb=J*S; Ya=(I-1)*S+1; Yb=I*S; for Ix=Xa:1:Xb for Iy=Ya:1:Yb HoIogram(Iy,Ix)=HoIodata(I,J); end end end end Max=max(max(HoIogram)); HoIogram=HoIogram/Max; figure; imshow(HoIogram); %以下是用matlab分別計算函數(shù)各抽樣點的傅里葉變換譜的幅角與模,并對各點的模歸一化 object=fft2(HoIogram); object=fftshift(object);%用matlab中的移譜函數(shù)fftshift( )將頻譜的低頻成分移到中心,以避免再現(xiàn)時像分散在邊緣 object=abs(object); object=1000*object/max(max(object)); figure; imshow(object);

資源截圖

代碼片段和文件信息

Image=imread(‘L.jpg‘);%用imread()函數(shù)讀入函數(shù)抽樣數(shù)據(jù)并保存到矩陣A中
N=512;
A=zeros(NN);
B=zeros(NN);
for?I=1:1:256
?????J=1:1:256
???????ImageNum=double(Image(IJ1));
???????A(IJ)=ImageNum/255;
???????B(IJ)=0;
?????end
end
figure;
imshow(A);
pi=3.1415926;
for?I=1:1:N
??????for?J=1:1:N
?????????R=rand(11);%生成一個元素在01之間均勻分布的隨機矩陣R
?????????B(IJ)=A(IJ)*sin(R*2*pi);%平滑函數(shù)的傅里葉變換譜
?????????A(IJ)=A(IJ)*cos(R*2*pi);
????F(IJ)=A(IJ)+j*B(IJ);
?????end
End%限制振幅的動態(tài)范圍提高編碼的精度
F=fft2(F);%作二維快速傅里葉變換FFT
Max=max(max(abs(F)));
F=F/Max;
A=real(F);
B=imag(F);
aIpha=0.5;%定義載波參數(shù)aIpha
for?I=1:1:N
???for?J=1:1:N
?????Xcos=(J-1)/127;
????A1(IJ)=cos(2*pi*aIpha*Xcos);
????B1(IJ)=sin(2*pi*aIpha*Xcos);
?????end
end%全息圖數(shù)據(jù)區(qū)
for?I=1:1:N
??????for?J=1:1:N
HoIodata(IJ)=0.5+0.5*(A(IJ)*A1(IJ)+B(IJ)*B1(IJ));
??????end
End
M=512;N=512;%定義全息圖的大小
Hologram=zeros(MM);
S=M/N;%定義每個抽樣單元大小
for?I=1:1:N
???for?J=1:1:N
Xa=(J-1)*S+1;
Xb=J*S;
Ya=(I-1)*S+1;
Yb=I*S;
for?Ix=Xa:1:Xb
????for?Iy=Ya:1:Yb
????HoIogram(IyIx)=HoIodata(IJ);
???????????????end
??????????end
?????end
end
Max=max(max(HoIogram));
HoIogram=HoIogram/Max;
figure;?
imshow(HoIogram);
%以下是用matlab分別計算函數(shù)各抽樣點的傅里葉變換譜的幅角與模并對各點的模歸一化
object=fft2(HoIogram);
object=fftshift(object);%用matlab中的移譜函數(shù)fftshift(?)將頻譜的低頻成分移到中心以避免再現(xiàn)時像分散在邊緣
object=abs(object);
object=1000*object/max(max(object));
figure;
imshow(object);

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????1576??2018-05-11?21:13??附件-matlab程序.m

-----------?---------??----------?-----??----

?????????????????1576????????????????????1


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