資源簡介
研究生數字信號處理課程作業,關于LMS最陡下降法的性能分析
代碼片段和文件信息
function?y?=?J(n0n1)
Rxx?=?[rxx(0)?rxx(1);rxx(1)?rxx(0)];
Ryx?=?[ryx(0);ryx(1)];
Hopt?=?inv(Rxx)*Ryx;
%求最優系數
h0?=?Hopt(1);
h1?=?Hopt(2);
Jmin?=?ryy(0)?-?Hopt‘*Ryx;
%?h0?=?-2:0.01:4;
%?h1?=?-4:0.01:2;
H?=?[n0;n1];
y?=?0.55?-?2*Ryx‘*H?+?H‘*Rxx*H;
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2012-10-21?11:06??exp1\
?????文件???????77364??2012-10-21?10:27??exp1\100次實驗中的H(n)的平均值的軌跡曲線.fig
?????文件????????5137??2012-10-21?10:09??exp1\e(n)曲線.fig
?????文件????????5890??2012-10-21?10:16??exp1\J(n)循環100次求平均.fig
?????文件????????5156??2012-10-21?10:10??exp1\J(n)曲線.fig
?????文件?????????269??2012-10-20?21:08??exp1\J.m
?????文件????????1117??2012-10-21?09:52??exp1\LMS.m
?????文件???????82185??2012-10-21?09:56??exp1\LMS的軌跡曲線.fig
?????文件?????????313??2012-10-20?21:59??exp1\main1.m
?????文件??????????58??2012-10-20?22:11??exp1\main3.m
?????文件????????1587??2012-10-21?10:26??exp1\main5.m
?????文件??????????47??2012-10-18?20:59??exp1\N0.m
?????文件??????????49??2012-10-18?19:19??exp1\N1.m
?????文件?????????100??2012-10-18?21:23??exp1\rNN.m
?????文件?????????129??2012-10-18?21:08??exp1\rxx.m
?????文件?????????104??2012-10-18?21:08??exp1\ryx.m
?????文件?????????121??2012-10-18?21:40??exp1\ryy.m
?????文件?????????749??2012-10-21?10:30??exp1\SMD.m
?????文件????????3931??2012-10-20?21:40??exp1\方差為0.05均值為0白噪音.fig
?????文件???????76060??2012-10-21?10:30??exp1\最陡下降法的軌跡曲線.fig
?????文件???????60550??2012-10-20?21:10??exp1\誤差性能曲面.fig
?????文件???????72559??2012-10-20?21:17??exp1\誤差性能等值曲線.fig
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