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  • 大小: 7KB
    文件類型: .m
    金幣: 1
    下載: 0 次
    發布日期: 2021-06-09
  • 語言: Matlab
  • 標簽:

資源簡介

在激光通信中,對于天線陣列,三維方向圖能夠幫助研究算法以提高通信的可靠!

資源截圖

代碼片段和文件信息

%%%%%%當波束指向陣面法向時的天線方向圖??
%在波束指向陣面法向時的最大增益值27dB??
A=27;??
%在波束指向陣面法向時的第一副瓣的增益值-1dB??
B=-1;??
%在波束指向陣面法向時的第一零深-30dB??
C=-30;??
%在波束指向陣面法向時的半功率點(3dB)寬度(rad)??
B_0=1.54*pi/180;??
%在波束指向陣面法向時的第一零點(rad)??
alpha_1=1.5*pi/180;??
%在波束指向陣面法向時的第一旁瓣的峰值所在角度(rad)??
alpha_1_5=2.5*pi/180;??
%波束指向,方位角rad??
alpha_0=60*pi/180;??
%波束指向,方位角rad??
beta_0=60*pi/180;??
%比例系數0epsilon=0.4;??
eta=0.5;??
%相控陣天線波束增益隨掃描角變化的控制因子??
K_0=cos(alpha_0)*cos(beta_0)/(sqrt((cos(alpha_0))^2+(cos(beta_0))^2*(sin(alpha_0))^2));??
%加權系數??
p=0;??
%沒有給出計算式,假定的??
d_beta=0.004;??
%相控陣天線波束隨掃描角展寬控制因子,可描述為??
M_0=p*d_beta^2+(4-4*K_0-p*B_0^2)*d_beta/(2*B_0)+K_0;??
%NewtonDown為牛頓下山法,可在Matlab書籍中找到,這里直接給出了計算結果??
%TwoStep為兩步迭代法,可在Matlab書籍中找到,這里直接給出了計算結果??
%%%%%%%%%?計算sin(x)=0.707*x%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%??
%?x_0(1)=NewtonDown(‘sin(x)-x*0.707‘-1.57-11.0e-4);??
%?x_0(2)=0;??
%?x_0(3)=NewtonDown(‘sin(x)-x*0.707‘11.571.0e-4);??
x_0=[-1.391801.3918];??
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%??
%%%%%%%%%?計算sin(x)=x*C/B??%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%??
%?k=1;??
%?for?i=0:3??
%?a1=0+i*2*pi;??
%?b1=pi/2+i*2*pi;??
%?x2(k)=TwoStep(‘sin(x)-x*10^(-1.45)‘a1b111.0e-4);??
%?k=k+1;??
%?a2=pi*0.5959+i*2*pi;??
%?b2=pi+i*2*pi;??
%?x2(k)=NewtonDown(‘sin(x)-x*10^(-1.45)‘a2b21.0e-4);??
%?k=k+1;??
%?end??
%?i=4;??
%?a1=0+i*2*pi;??
%?b1=pi/2+i*2*pi;??
%?x2(k)=TwoStep(‘sin(x)-x*10^(-1.45)‘a1b111.0e-4);??
%?k=k+1;??
%?a2=pi/2+0.0001*pi+i*2*pi;??
%?b2=pi+i*2*pi;??
%?x2(k)=NewtonDown(‘sin(x)-x*10^(-1.45)‘a2b21.0e-4);??
%?j=1;??
%?while?(k>1)??
%?????x22(j)=-x2(k);??
%?????j=j+1;??
%?????k=k-1;??
%?end??
%?x_2=cat(2x22x2);??
x_2=[-26.995-26.3398-21.1428-19.6195-15.1408-13.0477-9.0962-6.5165-3.033703.03376.51659.096213.047715.140819.619521.142826.339826.995];??
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%??
??
%%%%%%%%%%計算?sin(x)=x*C/(0.707*A)%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%??
%?k=1;??
%?for?i=0:75??
%?a1=0+i*2*pi;??
%?b1=pi/2+i*2*pi;??
%?x1(k)=TwoStep(‘sin(x)-x*10^(-2.85)/0.707‘a1b111.0e-4);??
%?k=k+1;??
%?a2=pi*0.5959+i*2*pi;??
%?b2=pi+i*2*pi;??
%?x1(k)=NewtonDown(‘sin(x)-x*10^(-2.85)/0.707‘a2b21.0e-4);??
%?k=k+1;??
%?end??
%???
%?for?i=76:79??
%?a1=0+i*2*pi;??
%?b1=pi/2-0.0001*pi+i*2*pi;??
%?x1(k)=TwoStep(‘sin(x)-x*10^(-2.85)/0.707‘a1b111.0e-4);??
%?k=k+1;??
%?a2=pi/2+0.00001*pi+i*2*pi;??
%?b2=pi+i*2*pi;??
%?x1(k)=NewtonDown(‘sin(x)-x*10^(-2.85)/0.707‘a2b21.0e-4);??
%?k=k+1;??
%?end??
%?j=1;??
%?k=k-1;??
%?while?(k>1)??
%?????x11(j)=-x1(k);??
%?????j=j+1;??
%?????k=k-1;??
%?end??
%?x_1=cat(2x11x1);??
x_1=[-498.0419-497.8389-491.8457-491.4688-485.6207-485.1274-479.3845-478.7972-473.142-472.4734-466.8951-466.1538-460.6452-459.8374-454.3928-453.5233-448.1385-447.2112-441.8827-440.9007-435.6255-434.5915-429.3671-428.2835-423.1078-421.9764-416.8476-415.6702-410.5867-409.3648-404.

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