%該計劃的目的是模擬AOA估計算法的角度
%一般天線陣規(guī)格
D?=?input?（‘Number?Of?Elements?:?‘）?;未知節(jié)點
N?=?input?（‘Number?Of?Users?:?‘）?;信標節(jié)點
L?=?input?（‘Number?Of?Samples?:?‘）?;%樣本??總節(jié)點數(shù)
P?=?input?（‘Signal?To?Noise?Ratio?Per?Sample?:?‘）?;%信噪比
%Input?Received?Signals?Arrival?輸入到達的的信號
for?I?=?1?:?N
????A?（?I?）?=?input?（‘The?Signal?Arrival?Phase?Angle?:?‘）?;?信號到達相位角
????A?（?I?）?=?A?（?I?）?*?pi?/?180?;
end
H?=?randint?（?N??L?）?;N*L維的矩陣??值隨機0或者1
%Estimation?of?The?Covariance?Matrix???協(xié)方差矩陣估計
S?=?zeros?（?D??N?）?;?
Rp?=?zeros?（?D??D?）?;
for?K?=?1?:?L??總節(jié)點數(shù)?
????for?J?=?1?:?N???信標節(jié)點數(shù)
????????for?I?=?1?:?D???未知節(jié)點數(shù)
????????????S?（?I??J?）?=?exp?（?i*（?pi??*?（?I?-?1?）?*?cos?（?A?（?J?）?）?）?）??;??
????????end
????end
????S?=?awgn?（?S?*?H?（?:??K?）??P?）?;
????Rp?=?Rp?+?S?*?S‘?;
end
Rp?=?Rp?/