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資源簡介

用matlab實現(xiàn)的用直接法來實現(xiàn)GPS姿態(tài)測量算法。

資源截圖

代碼片段和文件信息

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%???姿態(tài)測量仿真?(直接法)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

function?[sigmaP?sigmaY?sigmaR]=?zitaiError(sigma?L?sigmabaseline);

if?nargin?==?0
????sigma?=?[4?5?6];???????%???x?yz的偏差(mm)
????L?=?[20?20];??????????%???基線長(m)
????sigmabaseline?=?0;????%????基線對x,y,z偏差的影響(mm)?
end

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%???俯仰角誤差
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

sigmaMax?=?max(sigma);
sigmaP?=?(sigmaMax?+?sigmabaseline)?/?(L(1)?*?250)*180/3.14?;??%???俯仰角的標準差
errorP?=?sigmaP?.*?randn(1?250);????????????????????%???俯仰角的誤差值

figure(1);
plot(errorP);
errorMeanP?=?mean(errorP);
errorMeanP
errorStdP?=?std(errorP);
errorStdP
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%???航偏角誤差
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

minCosP?=?min(cos(errorP));
sigmaMax?=?max(sigma(11:2));
sigmaY?=?(sigmaMax?+?sigmabaseline)*180/3.14?/?(L(1)?*?250?*?minCosP);??%???航偏角標準差
errorY?=?sigmaY?.*?randn(1?250);??%???航偏角誤差值

figure(2);
plot(errorY);
errorMeanY?=?mean(errorY);
errorMeanY
errorStdY?=?std(errorY);
errorStdY

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%???橫滾角誤差
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

sigmaX2?=?cos(errorY)?.^?2?.*?sigma(1)?.^2?+?sin(errorY)?.^?2?.*?sigma(2)?.^?2;
sigmaZ2?=?sin(errorP)?.^?2?.*?sin(errorY)?.^?2?.*?sigma(1)?.^?2?+?sin(errorP)?.^?2?.*?cos(errorY)?.^?2?.*?sigma(2)?.^?2?+?cos(errorP)?.^?2?.*?sigma(3)?.^?2;

x?=?sqrt(sigmaX2)?.*?randn(1?250);
y?=?sqrt(sigmaZ2)?.*?randn(1?250);

sigmaMax?=?max([abs(x)?abs(y)]);
sigmaR?=?(sigmaMax?+?sigmabaseline)*180/3.14?/?(L(2)?*?250);????%??橫滾角標準差?
errorR?=?sigmaR?.*?(randn(1?250)*60);???%???橫滾角誤差值

figure(3);
plot(errorR);
errorMeanR?=?mean(errorR);
errorMeanR
errorStdR?=?std(errorR);
errorStdR




?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

????.CA....??????1819??2007-04-08?21:28??基于直接法的GPS姿態(tài)測量仿真程序\directattitudeError.m

????.C.D...?????????0??2009-11-13?09:59??基于直接法的GPS姿態(tài)測量仿真程序

-----------?---------??----------?-----??----

?????????????????1819????????????????????2


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