%%FileName:signal_test1.m
%%DesignedBy:
%%Date:10.22.2018
%%O_data?：原始數(shù)據(jù)
%%N_sample?：采樣次數(shù)
function?[]?=?signal_test1（power）
%%?生成偽隨機(jī)序列（原碼）
pngen?=?commsrc.pn（‘NumBitsOut‘2^power）;????????%?產(chǎn)生?PN?（偽隨機(jī)噪聲）信號包
data?=?generate（pngen）;???????????%?產(chǎn)生?2^power?PRBS?隨機(jī)序列
fs?=?1e6;???????%?信號頻率為?1MHz
Ts=1/fs;????????%?信號周期
N_sample?=?128;???????%?采樣次數(shù)為128個
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%?生成NRZ?RZ碼
NRZ?=?[];???????%?NRZ波形存放
RZ?=?[];????????%?RZ波形存放
for?i=1:length（data）??????%?采樣的同時也是對信號進(jìn)行NRZ與RZ變換?????????
????for?j=1:N_sample????????%?NRZ變換
????????NRZ（（i-1）*N_sample+j）=data（i）;
????end
????for?j=1:（N_sample/2）????????%?RZ變換
????????RZ（（i-1）*N_sample+j）=data（i）;
????????RZ（（i-1）*N_sample+j+N_sample/2）=0;
????end????
end?
figure（1）???????%?繪制NRZ，RZ波形圖
subplot（2?2?1）;plot（（0:1:N_sample*length（data）-1）*Ts/N_sample?RZ）;grid?on;axis（[0?length（data）*Ts?-2?2]）;title（‘RZ波形‘）;xlabel（‘S‘）
subplot（2?2?2）;plot（（0:1:N_sample*length（data）-1）*Ts/N_sample?NRZ）;grid?on;axis（[0?length（data）*Ts?-2?2]）;title（‘NRZ波形‘）;xlabel（‘S‘）
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%?生成AMI碼
AMI?=?zeros（size（data））;
%?number1記錄原碼中1的數(shù)量
number1?=?0;
%?number0記錄原碼中0的數(shù)量
number0?=?0;
%?生成AMI碼
for?i=1:length（data）
????if?data（i）==1
????????number1?=?number1+1;
????????if?mod（number12）==0
????????????AMI（i）?=?+1;????????%?原碼中偶數(shù)個1為-1
????????end
????????if?mod（number12）==1
????????????AMI（i）?=?-1;????????%?原碼中奇數(shù)個1為+1
????????end
????end
????if?data（i）==0
????????number0?=?number0+1;????????%?原碼中的0保持不變
????????AMI（i）?=?0;
????end
end
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%%?生成并繪制HDB3碼
HDB?=?zeros（size（data））;
%?給每個0000小節(jié)加V

for?i=?1:length（data）
????%?AMI中的-1和+1保持不變
????????if?abs（AMI（i））==1
????????????HDB（i）?=?AMI（i）;
????????end
????%
end
for?j=?1:?（length（data）-3）??????%連續(xù)的四個0第三個0設(shè)為V，V用2表示
????????if??（（AMI（j）?==?0）?&&?（AMI（j+1）?==?0）?&&?（AMI（j+2）?==?0）?&&?（AMI（j+3）?==?0））
????????????HDB（j+3）?=?2;
????????????HDB（j+2）?=?0;
????????????HDB（j+1）?=?0;
????????????HDB（j）?=?0;
????????????j?=?j+3;
????????end
end


%?每兩個V極性相反
number2?=?0;
for?i=1:length（data）
????if?HDB（i）==2
????????number2?=?number2+1;
????????if?mod（number22）==0
????????????HDB（i）?=?+2;
????????end
????????if?mod（number22）==1
????????????HDB（i）?=?-2;
????????end
????end
end

%?統(tǒng)計(jì)每2個V之間非零脈沖個數(shù)，若偶數(shù)，則第2個V所在小節(jié)的第1個0變?yōu)锽
firstV=0;
secondV=0;
number3=0;
for?i=1:length（data）
????%?找到第一個V
????if?abs（HDB（i））?==?2
????????firstV?=?i;
?????