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  • 大小: 4KB
    文件類型: .m
    金幣: 1
    下載: 0 次
    發布日期: 2021-06-18
  • 語言: Matlab
  • 標簽: 2DPCA??

資源簡介

提取Gabor特征,用2DPCA進行人臉識別。在Yale數據庫上測試,識別率較高,速度很快。

資源截圖

代碼片段和文件信息

clear;?
clear?all;
facesz?=?[25?25];?%?face?size
sampleRate?=?6;?%?Gabor降采樣率
gAngle?=?0:1:7;?%?4個Gabor核參數
gScale?=?0:4;
gShape?=?1.8*pi;
gWinLen?=?0;?%?Gabor核的長寬,0表示自行計算
N_Class=15;
N_face=1;
a=[];
W=25*5
H=25*8
img_per=[];
img_class=[];
img_vector=[];
img_face=[];
MT=zeros(WH);
temp=zeros(WH);
A=zeros(WW);
L=[];
T=[];
K=[];
right=0;
err=0;
I=[];
img1_face=[];
dd=70;
M=N_Class*N_face;

???[g?gWinLen]?=?genGaborKernel(gAnglegScalegShapegWinLen);
???for?i=1:N_Class
????S=zeros(WH);
????for?j=1:N_face
????????gabor_image=[];
????????img_per=[];
????????D1=[];
??????a=[‘C:\Users\john?archie\Desktop\52920923Gabor_face\Gabor_face\Yalefaces\‘?num2str(i)?‘\s‘?num2str(j)?‘.bmp‘]
??????%??a=[‘C:\Documents?and?Settings\Administrator\桌面\Gabor_face\ATfaces\‘?num2str(i)?‘\‘?num2str(j)?‘.bmp‘]
?????????%a=[‘C:\Documents?and?Settings\Administrator\桌面\hmm_matlab\hmm_matlab\face\s‘?num2str(i)?‘\‘?num2str(j)?‘.jpg‘];?
?????????I=imread(a);
????????
????I1=imresize(?I?[25?25]?‘bilinear‘?);
??????tic
?????[?GgWinLen?]?=?genGaborKernelF(?ggWinLen?facesz?);
?????gabor_image?=?gaborConvF(double(I1)GgWinLen)
?????%size(gabor_image);
?????toc
???????D1=cell2mat((gabor_image));
????????imshow(uint8(D1));
?????????%?for?k=1:W
??????????%??p=I(k:);?
??????????%??img_per=[img_perp];
?????????%?end
?????????%img_per=reshape(IW*H1);
????????img_per=D1;
?????????T=[T?img_per];
?????????MT=MT+1/M*(img_per);
?????????S=1/N_face*(img_per)+S;
????end
????K=[K?S];
end
size(MT)
size(K)
size(T)
for?n=1:N_Class*N_face
??temp=(T(:H*(n-1)+1:H*n))-MT;
??A=1/M*temp*temp‘+A;
end
L=A;
size(L)
[S?V]=eig(L);

L_eig_vec?=?[];
for?i?=?1?:?size(S2)?
????if(?V(ii)>1?)
????????L_eig_vec?=?[L_eig_vec?S(:i)];
????end
end
%L_eig_vec;
[u1s1v1]=svd(L);
u1
s1
size(v1)
figure(2);
imshow(v1)
C=[];
C=v1(:1:dd);
figure(3);
size(C)
imshow(C)
Y=[];
B=[];
X=[];
for?n=1:N_Class*N_face
??X=(T(:H*(n-1)+1:H*n));
??B=X‘*C;
??Y=[Y?B];
end
size(B)
size(Y)
%B
%Y
B1=[];
X1=[];
S1=[];
for?n=1:N_Class
??X1=(K(:H*(n

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