91av视频/亚洲h视频/操亚洲美女/外国一级黄色毛片 - 国产三级三级三级三级

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    文件類型: .zip
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    發布日期: 2023-08-31
  • 語言: Matlab
  • 標簽:

資源簡介

基于MATLAB的樹葉圖像特征分類識別,圖像分析處理 分割 特征提取 分類識別等

資源截圖

代碼片段和文件信息

function?phi?=?invmoments(F)
%INVMOMENTS?Compute?invariant?moments?of?image.
%???PHI?=?INVMOMENTS(F)?computes?the?moment?invariants?of?the?image
%???F.?PHI?is?a?seven-element?row?vector?containing?the?moment
%???invariants?as?defined?in?equations?(11.3-17)?through?(11.3-23)?of
%???Gonzalez?and?Woods?Digital?Image?Processing?2nd?Ed.
%
%???F?must?be?a?2-D?real?nonsparse?numeric?or?logical?matrix.

%???Copyright?2002-2004?R.?C.?Gonzalez?R.?E.?Woods?&?S.?L.?Eddins
%???Digital?Image?Processing?Using?MATLAB?Prentice-Hall?2004
%???$Revision:?1.5?$??$Date:?2003/11/21?14:39:19?$

if?(ndims(F)?~=?2)?|?issparse(F)?|?~isreal(F)?|?~(isnumeric(F)?|?...
????????????????????????????????????????????????????islogical(F))
???error([‘F?must?be?a?2-D?real?nonsparse?numeric?or?logical?‘?...
??????????‘matrix.‘]);?
end

F?=?double(F);

phi?=?compute_phi(compute_eta(compute_m(F)));
??
%-------------------------------------------------------------------%
function?m?=?compute_m(F)

[M?N]?=?size(F);
[x?y]?=?meshgrid(1:N?1:M);
??
%?Turn?x?y?and?F?into?column?vectors?to?make?the?summations?a?bit
%?easier?to?compute?in?the?following.
x?=?x(:);
y?=?y(:);
F?=?F(:);
??
%?DIP?equation?(11.3-12)
m.m00?=?sum(F);
%?Protect?against?divide-by-zero?warnings.
if?(m.m00?==?0)
???m.m00?=?eps;
end
%?The?other?central?moments:??
m.m10?=?sum(x?.*?F);
m.m01?=?sum(y?.*?F);
m.m11?=?sum(x?.*?y?.*?F);
m.m20?=?sum(x.^2?.*?F);
m.m02?=?sum(y.^2?.*?F);
m.m30?=?sum(x.^3?.*?F);
m.m03?=?sum(y.^3?.*?F);
m.m12?=?sum(x?.*?y.^2?.*?F);
m.m21?=?sum(x.^2?.*?y?.*?F);

%-------------------------------------------------------------------%
function?e?=?compute_eta(m)

%?DIP?equations?(11.3-14)?through?(11.3-16).

xbar?=?m.m10?/?m.m00;
ybar?=?m.m01?/?m.m00;

e.eta11?=?(m.m11?-?ybar*m.m10)?/?m.m00^2;
e.eta20?=?(m.m20?-?xbar*m.m10)?/?m.m00^2;
e.eta02?=?(m.m02?-?ybar*m.m01)?/?m.m00^2;
e.eta30?=?(m.m30?-?3?*?xbar?*?m.m20?+?2?*?xbar^2?*?m.m10)?/?m.m00^2.5;
e.eta03?=?(m.m03?-?3?*?ybar?*?m.m02?+?2?*?ybar^2?*?m.m01)?/?m.m00^2.5;
e.eta21?=?(m.m21?-?2?*?xbar?*?m.m11?-?ybar?*?m.m20?+?...
???????????2?*?xbar^2?*?m.m01)?/?m.m00^2.5;
e.eta12?=?(m.m12?-?2?*?ybar?*?m.m11?-?xbar?*?m.m02?+?...
???????????2?*?ybar^2?*?m.m10)?/?m.m00^2.5;

%-------------------------------------------------------------------%?
function?phi?=?compute_phi(e)

%?DIP?equations?(11.3-17)?through?(11.3-23).

phi(1)?=?e.eta20?+?e.eta02;
phi(2)?=?(e.eta20?-?e.eta02)^2?+?4*e.eta11^2;
phi(3)?=?(e.eta30?-?3*e.eta12)^2?+?(3*e.eta21?-?e.eta03)^2;
phi(4)?=?(e.eta30?+?e.eta12)^2?+?(e.eta21?+?e.eta03)^2;
phi(5)?=?(e.eta30?-?3*e.eta12)?*?(e.eta30?+?e.eta12)?*?...
?????????(?(e.eta30?+?e.eta12)^2?-?3*(e.eta21?+?e.eta03)^2?)?+?...
?????????(3*e.eta21?-?e.eta03)?*?(e.eta21?+?e.eta03)?*?...
?????????(?3*(e.eta30?+?e.eta12)^2?-?(e.eta21?+?e.eta03)^2?);
phi(6)?=?(e.eta20?-?e.eta02)?*?(?(e.eta30?+?e.eta12)^2?-?...
?????????????????????????????????(e.eta21?+?e.eta03)^2?)?+?...

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2012-12-21?20:44??新建文件夾\
?????文件????????3319??2012-12-12?15:37??新建文件夾\invmoments.m
?????文件????????1209??2012-12-21?20:42??新建文件夾\TASK2.m
?????文件?????5617342??2012-12-05?20:26??新建文件夾\test.tif
?????文件?????????573??2012-12-16?14:56??新建文件夾\train.m
?????文件?????????570??2012-12-16?15:29??新建文件夾\train2.m
?????文件?????????564??2012-12-16?16:10??新建文件夾\train3.m
?????文件??????456772??2006-12-29?18:54??新建文件夾\train_1.tif
?????文件???????98456??2006-12-29?19:11??新建文件夾\train_2.tif
?????文件?????1156394??2006-12-30?16:11??新建文件夾\train_3.tif

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