資源簡(jiǎn)介
對(duì)共享單車的排隊(duì)網(wǎng)絡(luò)分析,建模并用matlab仿真,所有源代碼
代碼片段和文件信息
function?m1=mA(s0alpha)
syms?k1
K=200;
M=5;
lambda1=8;
miu1=10;
v1=30;
%alpha=0.07;
theta1=40;
%s0=0.06;
tao1=theta1*s0;
%%?%%%%%%%%%%%%%%%%%%%%%%%%%%區(qū)域1
%%?%%%%%%%%%%%%定義矩陣Q00
%A00=sym([]);
A00(11)=-(miu1+tao1);
A00(K+1K+1)=-(lambda1+K*alpha);
for?i=2:K-1
????A00(ii)=-(lambda1+miu1+tao1+(i-1)*alpha);
end
for?i=K
????A00(ii)=-(lambda1+miu1+(i-1)*alpha);
end
%另外三條斜線
for?i=1:K
????A00(i+1i)=lambda1;
????A00(ii+1)=miu1;
end
for?i=1:K-1
?????A00(ii+2)=tao1;
end
%%?%%%%%%%%%%%%定義矩陣Q11
%A11=sym([]);
A11(11)=-(miu1+tao1);
A11(KK)=-(lambda1+(K-1)*alpha);
for?i=2:K-2
????A11(ii)=-(lambda1+miu1+tao1+(i-1)*alpha);
end
for?i=K-1
????A11(ii)=-(lambda1+miu1+(i-1)*alpha);
end
%另外三條斜線
for?i=1:K-1
????A11(i+1i)=lambda1;
????A11(ii+1)=miu1;
end
for?
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2019-01-19?11:48??alphadiedaiw05\
?????文件????????3342??2018-10-12?23:28??alphadiedaiw05\mA.m
?????文件????????3351??2018-10-12?23:29??alphadiedaiw05\mB.m
?????文件????????3366??2018-10-12?23:29??alphadiedaiw05\mC.m
?????文件????????3356??2018-10-12?23:29??alphadiedaiw05\mD.m
?????文件????????3364??2018-10-12?23:30??alphadiedaiw05\mE.m
?????文件????????3365??2018-10-12?23:30??alphadiedaiw05\mF.m
?????文件????????3370??2018-10-12?23:30??alphadiedaiw05\mG.m
?????文件????????3335??2018-10-12?23:30??alphadiedaiw05\mH.m
?????文件????????3375??2018-10-12?23:30??alphadiedaiw05\mI.m
?????文件????????3468??2018-10-12?23:28??alphadiedaiw05\mJ.m
?????文件???????10990??2018-10-18?05:21??alphadiedaiw05\mT.m
?????文件????????2249??2018-10-18?05:03??alphadiedaiw05\main.m
評(píng)論
共有 條評(píng)論