資源簡介
這是一個可以實現簡單抽獎的程序,大家可以在它的基礎上進行進一步的修改,希望大家能相互學習,相互進步,我也是在學習這個的進一步開發~~
代碼片段和文件信息
function?varargout?=?yaojiang5(varargin)
gui_Singleton?=?1;
gui_State?=?struct(‘gui_Name‘???????mfilename?...
???????????????????‘gui_Singleton‘??gui_Singleton?...
???????????????????‘gui_OpeningFcn‘?@yaojiang5_OpeningFcn?...
???????????????????‘gui_OutputFcn‘??@yaojiang5_OutputFcn?...
???????????????????‘gui_LayoutFcn‘??[]??...
???????????????????‘gui_Callback‘???[]);
if?nargin?&&?ischar(varargin{1})
????gui_State.gui_Callback?=?str2func(varargin{1});
end
if?nargout
????[varargout{1:nargout}]?=?gui_mainfcn(gui_State?varargin{:});
else
????gui_mainfcn(gui_State?varargin{:});
end
function?yaojiang5_OpeningFcn(hobject?eventdata?handles?varargin)
handles.output?=?hobject;
guidata(hobject?handles);
function?varargout?=?yaojiang5_OutputFcn(hobject?ev
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????2893??2009-09-26?18:15??搖獎臺程序V2[1].0\yaojiang5.fig
?????文件???????3725??2009-09-26?18:15??搖獎臺程序V2[1].0\yaojiang5.m
?????文件???????3584??2009-09-26?18:15??搖獎臺程序V2[1].0\yaojiang5_activex1
?????目錄??????????0??2010-06-10?22:04??搖獎臺程序V2[1].0
-----------?---------??----------?-----??----
????????????????10202????????????????????4
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