91av视频/亚洲h视频/操亚洲美女/外国一级黄色毛片 - 国产三级三级三级三级

  • 大小: 5.94MB
    文件類型: .zip
    金幣: 2
    下載: 0 次
    發(fā)布日期: 2023-11-09
  • 語言: Matlab
  • 標(biāo)簽: 車牌定位??

資源簡(jiǎn)介

對(duì)獲取到的車牌圖像用MATLAB進(jìn)行預(yù)處理(包括灰度化處理,二值化處理,中值濾波 等)邊緣化處理、形態(tài)學(xué)處理來確定車牌的位置。

資源截圖

代碼片段和文件信息

close?all;
clear?all;
clc;
pic=imread(‘che1.jpg‘);
figure(1);
imshow(pic);
picR=pic(::1);
picG=pic(::2);
picB=pic(::3);
g=rgb2gray(pic);
gmed=medfilt2(g);
[rc]=size(g);
figure(2);
imshow(gmed);
edgpic=edge(gmed‘roberts‘0.01);
figure(3);
imshow(edgpic);
data=edgpic;
?
%形態(tài)學(xué)處理
pic2=bwmorph(edgpic‘clean‘);
pic2=imclose(pic2strel(‘rectangle‘[830]));
pic2=imopen(pic2strel(‘rectangle‘[519]));
pic2=bwmorph(pic2‘dilate‘3);
figure(4);
imshow(pic2);
?
%車牌定位
for?i=1:3
????red(i)=0;gre(i)=0;blu(i)=0;
end
poz=zeros(rc);
dayblue=0;
%記錄色彩比對(duì)像素點(diǎn)
?
%%利用色彩模型比對(duì)
for?i=1:r
????for?j=1:c
????????if(picR(ij)>=0&&picR(ij)<25)
????????????red(1)=1;
????????end
????????if(picG(ij)>20&&picG(ij)<80)
?????????????gre(1)=1;
?????????end
?????????if(picB(ij)>40&&picB(ij)<180)
?????????????blu(1)=1;
?????????end
?????????if(red(1)==1&&gre(1)==1&&blu(1)==1)
?????????????poz(ij)=255;
?????????????dayblue=dayblue+1;
?????????end
?????????for?k=1:3
?????????????red(k)=0;gre(k)=0;blu(k)=0;
?????????end
????end
end
%?if(red(1)==1&&gre(1)==1&&blu(1)==1)
%?????poz(ij1)=255;dayblue=dayblue+1;
%?end
dilatenum=2;
figure(5);
imshow(poz(::));
%title(‘位置信息矩陣B‘);
pic3=zeros(rc);
for?i=1:r
????for?j=1:c
????????if(pic2(ij)==1&&poz(ij)==255)
????????????pic3(ij)=1;
????????end
????end
end
%figure;
%imshow(pic3);
?
pic3=bwmorph(pic3‘clean‘3);
pic3=bwmorph(pic3‘dilate‘1);
pic3=imclose(pic3strel(‘rectangle‘[830]));
pic3=imopen(pic3strel(‘rectangle‘[519]));
pic3=bwmorph(pic3‘dilate‘dilatenum);
%%計(jì)算聯(lián)通區(qū)域面積
?
figure(6);
imshow(pic3);
%title(‘位置信息矩陣C‘);
%確定端點(diǎn)坐標(biāo)
pozitionR1=0;
pozitionR2=0;
for?i=1:r
????RR(i)=sum(pic3(i:));
end
?
judgeR=40;
k=0;
for?i=1:r
????if(pozitionR1==0&&RR(i)~=0)
???????pozitionR1=i;
????end
????if(pozitionR1~=0&&pozitionR2==0&&RR(i)==0)
????????pozitionR2=i;
????????k=pozitionR2-pozitionR1;
????end
????if(k~=0&&k????????pozitionR1=0;
????????pozitionR2=0;
????????k=0;
????end
????if(k>judgeR)
????????break;
????end
end
?
?
pozitionC1=0;
pozitionC2=0;
for?i=1:c
????CC(i)=sum(pic3(:i));
end
judgeC=180;
k=0;
?
for?i=1:c
????if(pozitionC1==0&&CC(i)~=0)
????????pozitionC1=i;
????end
????if(pozitionC1~=0&&pozitionC2==0&&CC(i)==0)
????????pozitionC2=i;
????????k=pozitionC2-pozitionC1;
????end
????????if(k~=0&&k????????????pozitionC1=0;?
????????????pozitionC2=0;
????????????k=0;
????????end
????????if(k>judgeC)
????????????break;
????????end
end
chepaitu=zeros([pozitionR2-pozitionR1pozitionC2-pozitionC13]‘uint8‘);
for?i=pozitionR1:pozitionR2
????for?j=pozitionC1:pozitionC2
????????chepaitu(i-pozitionR1+1j-pozitionC1+11)=picR(ij);
????????chepaitu(i-pozitionR1+1j-pozitionC1+12)=picG(ij);
????????chepaitu(i-pozitionR1+1j-pozitionC1+13)=picB(ij);??
????end?
end
?
figure(7);
imshow(chepaitu);


?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件?????6354689??2019-09-17?18:58??車牌定位\che1.jpg
?????文件????????2975??2019-10-09?14:37??車牌定位\L1.m

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