91av视频/亚洲h视频/操亚洲美女/外国一级黄色毛片 - 国产三级三级三级三级

  • 大小: 12KB
    文件類型: .zip
    金幣: 2
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    發布日期: 2023-12-20
  • 語言: Matlab
  • 標簽: 條碼識別??

資源簡介

對一維條型碼圖像識別matlab程序,能夠識別出一維條形碼的碼字。

資源截圖

代碼片段和文件信息

I=imread(‘barcode.jpg‘);%read?image?from?drive;
I=im2bw(I);?????????????
imshow(I);??
hold?on;
[xy]=ginput(2);????????%get?data?from?click?mouse
u1=x(1);
u2=y(1);
v1=x(2);
v2=y(2);
line(xy);??????????????%paint?the?line?between?2?point?at?click?mouse
a?=?[u1:1:v1];??????????%find?out?function?line?between?2?point
if?(u1~=v1)?&?(u2~=v2)
????g?=?round(((v2-u2)/(v1-u1))*a?+?u2?-(u1/(v1-u1)));
elseif?(u1==v1)
????a?=?u1;
end??????????????????????
i=1;????????????????????%find?the?value?each?pixel?that?the?line?go?through
h=v1-u1+1;
b=[1:1:h];
for?a=u1:v1
????if?(I(ga)==0)
????????b(i)=1;
????????i=i+1;
????elseif?(I(ga)==1)
????????b(i)=0;
????????i=i+1;
????end
end
c=b
i=1;????????????????%find?number?pixels?of?each?line?in?barcode?picture;
s=[1:1:60];
for?k=1:60
????j=0;
????if?c(i)==0
????????while?(c(i)==0)&(i<=h)
????????????j=j+1;
????????????i=i+1;
????????????s(k)=j;
????????end
????elseif?c(i)==1
????????while?(c(i)==1)&(i<=h)
????????????j=j+1;
????????????i=i+1;
????????????s(k)=j;
????????end
????end
end
mau=s(2);???????%the?first?line?is?the?sample?for?barcodein?another?line?is?ratio?with?this
q=s./mau;
p=round(q);?????
doc1=[1:1:6];???%decode?
k=1;
for?i=5:4:25
????if?(p(i)==3)&?(p(i+1)==2)?&(p(i+2)==1)?&(p(i+3)==1)
????????doc1(k)=0
????elseif?(p(i)==2)&?(p(i+1)==2)?&(p(i+2)==2)?&(p(i+3)==1)
????????doc1(k)=1??
????elseif?(p(i)==2)&?(p(i+1)==1)?&(p(i+2)==2)?&(p(i+3)==2)
????????doc1(k)=2
????elseif?(p(i)==1)&?(p(i+1)==4)?&(p(i+2)==1)?&(p(i+3)==1)
????????doc1(k)=3
????elseif?(p(i)==1)&?(p(i+1)==1)?&(p(i+2)==3)?&(p(i+3)==2)
????????doc1(k)=4
????elseif?(p(i)==1)&?(p(i+1)==2)?&(p(i+2)==3)?&(p(i+3)==1)
????????doc1(k)=5
????elseif?(p(i)==1)&?(p(i+1)==1)?&(p(i+2)==1)?&(p(i+3)==4)
????????doc1(k)=6
????elseif?(p(i)==1)&?(p(i+1)==3)?&(p(i+2)==1)?&(p(i+3)==2)
????????doc1(k)=7
????elseif?(p(i)==1)&?(p(i+1)==2)?&(p(i+2)==1)?&(p(i+3)==3)
????????doc1(k)=8
????elseif?(p(i)==3)&?(p(i+1)==1)?&(p(i+2)==1)?&(p(i+3)==2)
????????doc1(k)=9
????end
????k=k+1;
end
doc2=[1:1:6];
k=1;
for?i=34:4:54
????if?(p(i)==3)&?(p(i+1)==2)?&(p(i+2)==1)?&(p(i+3)==1)
????????doc2(k)=0
????elseif?(p(i)==2)&?(p(i+1)==2)?&(p(i+2)==2)?&(p(i+3)==1)
????????doc2(k)=1??
????elseif?(p(i)==2)&?(p(i+1)==1)?&(p(i+2)==2)?&(p(i+3)==2)
????????doc2(k)=2
????elseif?(p(i)==1)&?(p(i+1)==4)?&(p(i+2)==1)?&(p(i+3)==1)
????????doc2(k)=3
????elseif?(p(i)==1)&?(p(i+1)==1)?&(p(i+2)==3)?&(p(i+3)==2)
????????doc2(k)=4
????elseif?(p(i)==1)&?(p(i+1)==2)?&(p(i+2)==3)?&(p(i+3)==1)
????????doc2(k)=5
????elseif?(p(i)==1)&?(p(i+1)==1)?&(p(i+2)==1)?&(p(i+3)==4)
????????doc2(k)=6
????elseif?(p(i)==1)&?(p(i+1)==3)?&(p(i+2)==1)?&(p(i+3)==2)
????????doc2(k)=7
????elseif?(p(i)==1)&?(p(i+1)==2)?&(p(i+2)==1)?&(p(i+3)==3)
????????doc2(k)=8
????elseif?(p(i)==3)&?(p(i+1)==1)?&(p(i+2)==1)?&(p(i+3)==2)
????????doc2(k)=9
????end
????k=k+1;
end?

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????27764??2008-10-27?06:41??barcode.JPG
?????文件????????1578??2009-05-27?13:05??license.txt
?????文件????????2931??2008-10-27?19:23??runprogram.m

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