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資源簡介

OFDMA功率分配經典文獻 "A Low Complexity Algorithm for Proportional Resource Allocation in OFDMA Systems"的相應MATLAB代碼

資源截圖

代碼片段和文件信息

function?[envIQ]=?chtry(userNumsampleNumfm)

%WLAN?channel?modeling
%Zukang?Shen
%04/15/02


%Ts=50e-9*10000*2/20;?%time?sample?interval
Ts=1e-3;
N=200;?%number?of?input?waves
n=[0:N-1];
cita=2*pi*n/N;?%input?angles

for?user=1:userNum
alfa1=randn(1N);?%magnitudes?of?input?waves?tap?1
alfanormed(1:)=alfa1/sqrt(sum(alfa1.^2));?%normalized?magnitude?tap?1
alfa2=randn(1N);?%magnitudes?of?input?waves?tap?2
alfanormed(2:)=alfa2/sqrt(sum(alfa2.^2));?%normalized?magnitude?tap?2
alfa3=randn(1N);?%magnitudes?of?input?waves?tap?3
alfanormed(3:)=alfa3/sqrt(sum(alfa3.^2));?%normalized?magnitude?tap?3
alfa4=randn(1N);?%magnitudes?of?input?waves?tap?4
alfanormed(4:)=alfa4/sqrt(sum(alfa4.^2));?%normalized?magnitude?tap?4
alfa5=randn(1N);?%magnitudes?of?input?waves?tap?5
alfanormed(5:)=alfa5/sqrt(sum(alfa5.^2));?%normalized?magnitude?tap?5
alfa6=randn(1N);?%magnitudes?of?input?waves?tap?6
alfanormed(6:)=alfa6/sqrt(sum(alfa6.^2));?%normalized?magnitude?tap?6

phaseinit1=randn(1N);
phaseinit(1:)=phaseinit1*2*pi/max(phaseinit1);?%initial?phases?tap?1
phaseinit2=randn(1N);
phaseinit(2:)=phaseinit2*2*pi/max(phaseinit2);?%initial?phases?tap?2
phaseinit3=randn(1N);
phaseinit(3:)=phaseinit3*2*pi/max(phaseinit3);?%initial?phases?tap?3
phaseinit4=randn(1N);
phaseinit(4:)=phaseinit4*2*pi/max(phaseinit4);?%initial?phases?tap?4
phaseinit5=randn(1N);
phaseinit(5:)=phaseinit5*2*pi/max(phaseinit5);?%initial?phases?tap?5
phaseinit6=randn(1N);
phaseinit(6:)=phaseinit6*2*pi/max(phaseinit6);?%initial?phases?tap?6

%using?one-sided?exponential?profile
to=1*Ts;
tt=[0:5]*Ts;
g=exp(-tt/to);%relative?engery?for?the?6?taps

????for?j=1:6%%multi-path
????????for?i=0:sampleNum-1%time-variety
????????????t=i*Ts;
????????????is=g(j)*sum(alfanormed(j:).*cos(2*pi*fm*t*cos(cita)+phaseinit(j:)));
????????????qs=g(j)*sum(alfanormed(j:).*sin(2*pi*fm*t*cos(cita)+phaseinit(j:)));
????????????I(userji+1)=is;
????????????Q(userji+1)=qs;
????????????envs=sqrt(qs^2+is^2);
????????????env(userji+1)=envs;
????????end
????end

end

for?i=1:sampleNum
envtmp(i)=env(11i);
end
%?figure
%?stem([0:sampleNum-1]*Ts?20*log10(envtmp))
%?title(‘Rayleigh?Fading‘)
%?xlabel(‘t‘)
%?ylabel(‘r(t)‘)
%
%?figure
%?stem([0:sampleNum-1]*Ts?envtmp)
%?title(‘Rayleigh?Fading‘)
%?xlabel(‘t‘)
%?ylabel(‘r(t)‘)

clear?alfa1?alfa2?alfa3?alfa4?alfa5?alfa6?alfanormed?phaseinit1?phaseinit2?phaseinit3?phaseinit4?phaseinit5?phaseinit6
clear?phaseinit?is?qs?envs


?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

????I.A....????188456??2015-07-04?18:05??MATLAB-code-of-OFDMA-power-allocation\A_Low_Complexity_Algorithm_for_Proportional_Resource_Allocation_in_OFDMA_Systems.pdf

?????文件???????2548??2010-04-12?16:19??MATLAB-code-of-OFDMA-power-allocation\chtry.m

?????文件???????2089??2009-07-28?09:43??MATLAB-code-of-OFDMA-power-allocation\rheesub.m

?????文件????????953??2009-07-27?17:49??MATLAB-code-of-OFDMA-power-allocation\rootfinding.m

?????文件???????2594??2010-04-16?16:03??MATLAB-code-of-OFDMA-power-allocation\shenpowerallo.asv

?????文件???????2711??2010-04-16?16:38??MATLAB-code-of-OFDMA-power-allocation\shenpowerallo.m

?????文件???????5363??2010-04-13?20:43??MATLAB-code-of-OFDMA-power-allocation\SIPS04main.asv

?????文件???????5394??2010-04-16?17:17??MATLAB-code-of-OFDMA-power-allocation\SIPS04main.m

?????文件???????2218??2009-07-29?15:32??MATLAB-code-of-OFDMA-power-allocation\Untitled3.m

?????文件???????1585??2010-04-13?20:09??MATLAB-code-of-OFDMA-power-allocation\waterfilling.m

?????文件???????3283??2009-07-31?17:20??MATLAB-code-of-OFDMA-power-allocation\wongpowerallo.m

?????文件???????2823??2009-07-28?09:43??MATLAB-code-of-OFDMA-power-allocation\wongsuballo.m

?????目錄??????????0??2015-07-04?18:05??MATLAB-code-of-OFDMA-power-allocation

-----------?---------??----------?-----??----

???????????????220017????????????????????13


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