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資源簡介

基于simulink的RS編碼譯碼,分析其誤碼率,并畫出它的性能曲線。

資源截圖

代碼片段和文件信息

%?2014-5-7?11:15:36?commonkids
EbN0=-5:5;
load?ber0;
for?i=1:11
????SNR=EbN0(i)
????for?j=1:1
????????sim(‘RS_ber‘);
????????ber1(j)=ErrorVec(1);
????end
????ber2(i)=mean(ber1);
end
semilogy(EbN0ber2‘-bo‘);hold?on;
%legend();
hold?on;
semilogy(EbN0ber0‘-r*‘);
legend(‘經過RS編碼‘‘未經過RS編碼‘);
grid?on;
xlabel(‘SNR/dB‘);
ylabel(‘BER‘);
title(‘經過RS編碼和未經RS編碼的誤碼率對比‘);

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????5595??2020-09-19?00:26??RS?α┬δ-simulink\ber0.mat
?????文件???????26522??2020-09-19?00:26??RS?α┬δ-simulink\RS_ber.mdl
?????文件???????26042??2020-09-19?00:26??RS?α┬δ-simulink\RS_ber.mdl.autosave
?????文件?????????350??2020-09-19?00:26??RS?α┬δ-simulink\RS_main.asv
?????文件?????????406??2020-09-19?00:26??RS?α┬δ-simulink\RS_main.m
?????文件???????11260??2020-09-19?00:26??RS?α┬δ-simulink\RS?α┬δBPSK╡≈╓╞╡─┐╣╘δ╨╘─▄.fig
?????文件??????236278??2020-09-19?00:26??RS?α┬δ-simulink\╛?╣2RS?α┬δ║═╬┤╛?RS?α┬δ╡─╬≤┬δ┬╩╢╘?╚.bmp

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