function?[shed1sp1]=arrange（shed11sp11）
%?排序
shed1=shed11;
sp1=sp11;

%?根據?shed1（1:）的大小，重新排列?shed1，按由大到小的順序
for?i=1:sp1-1
????maxvalue=shed1（1i）;
????x=shed1（2i）;
????y=shed1（3i）;
????for?j=i+1:sp1
????????if?maxvalue????????????shed1（1i）=shed1（1j）;???shed1（2i）=shed1（2j）;?????shed1（3i）=shed1（3j）;
????????????shed1（1j）=maxvalue;?????shed1（2j）=x;??????????????shed1（3j）=y;
????????????maxvalue=shed1（1i）;?????x=shed1（2i）;??????????????y=shed1（3i）;
????????end
????end
end

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件??????437355??2009-11-13?09:19??image?segmation?shengzhang2\1.png
?????文件????????7168??2010-06-17?18:59??image?segmation?shengzhang2\Thumbs.db
?????文件??????568977??2010-06-05?10:56??image?segmation?shengzhang2\Z4.mat
?????文件?????????567??2009-05-04?20:18??image?segmation?shengzhang2\arrange.m
?????文件?????????357??2009-05-14?10:27??image?segmation?shengzhang2\listed.m
?????文件?????????540??2010-05-20?21:15??image?segmation?shengzhang2\ruzhan.m
?????文件????????7187??2010-06-05?09:21??image?segmation?shengzhang2\shengzhang.m
?????目錄???????????0??2012-10-30?10:40??image?segmation?shengzhang2\