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資源簡介

自己實現的sift特征提取的matlab代碼,可以計算特征描述子用于圖像匹配,不過速度有點慢

資源截圖

代碼片段和文件信息

function?desc=descriptor(keyptSOsigmmagangles)
cnt=size(keypt1);
nbp=4;
desc=zeros(cntnbp*nbp*8);
for?i=1:cnt
????
????o=floor((keypt(i3)-1)/O)+1;
????s=mod(keypt(i3)-1O)+1;
????[MNtemp]=size(mag{o});
????sigm0=2^((s+1)/S)*sigm;
%?????sigm0=2^(keypt(i3)/S)*sigm;
????sbp=3*sigm0;
????W=floor(sqrt(2)*sbp*(nbp+1)/2+0.5);
????xp=keypt(i1);
????yp=keypt(i2);
????theta0=keypt(i4);
????sin0=sin(theta0);
????cos0=cos(theta0);
????index=0;
????histo=zeros(1nbp*nbp*8);
????for?xs?=?xp?-?min(W?xp-1):?min((M?-?1)?xp?+?W)
????????for?ys?=?yp?-?min(W?yp-1)?:?min((N-1)?yp?+?W)
????????????dx=xp-xs;
????????????dy=yp-ys;
????????????if?dx^2+dy^2????????????????theta=angles{o}(xsyss);
????????????????theta=mod((theta-theta0)2*pi);
????????????????nx=(

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件?????231201??2004-04-04?21:22??sift\001.jpg

?????文件?????910766??2011-04-08?15:18??sift\d2.mat

?????文件???????2814??2011-04-07?16:03??sift\descriptor.m

?????文件???????1209??2011-04-07?15:33??sift\dog.m

?????文件???????4729??2011-04-08?15:18??sift\k2.mat

?????文件???????2512??2011-04-08?15:05??sift\local_max.m

?????文件???????1697??2011-04-07?20:05??sift\match.m

?????文件????????542??2011-04-08?15:05??sift\show.m

?????文件???????1759??2011-04-08?15:18??sift\sift.m

?????文件????1092484??2000-01-01?00:00??sift\t1.JPG

?????文件????1071674??2000-01-01?00:00??sift\t2.JPG

?????目錄??????????0??2011-04-08?15:17??sift

-----------?---------??----------?-----??----

??????????????3321387????????????????????12


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