function?b=CRC16_PDCCH（aport_UEX_RNTI）
%?=========================================================================
%?功能：計算16位的crc并對其加擾
%?輸入：????
%??????????a：需要進行CRC校驗的信息
%?????port_U：UE傳輸選擇的天線端口?0或1
%?????X_RNTI：RNTI擾碼序列
%?輸出：
%??????????b：將生成的16為校驗位添加到信息位后輸出
%?=========================================================================
L?=?16;
p?=?zeros（1L）;??????????????????????????????%?16位校驗位
lenI?=?length（a）;
G=[1?0?0?0?1?0?0?0?0?0?0?1?0?0?0?0?1];???????%?生成多項式，由低位到高位
X_AS=[0000000000000000;
??????0000000000000001];??????%?UE傳輸端口選擇

DataCRC=[ap];
for?k=1:lenI
????if?DataCRC（k）==1
????????for?j=1:length（G）
????????????DataCRC（k+j-1）=xor（DataCRC（k+j-1）G（j））;
????????end
????end
end
for?k=1:L
????p（k）=DataCRC（lenI+k）;
end
p=mo

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件???????1039??2012-07-02?20:39??PDCCH\CRC16_PDCCH.m

?????文件????????831??2012-07-02?20:39??PDCCH\crcCheck16.m

?????文件???????3390??2012-07-02?20:39??PDCCH\DCI_check.asv

?????文件???????3406??2012-07-02?20:39??PDCCH\DCI_check.m

?????文件???????1746??2012-07-02?20:39??PDCCH\de_interleaver.m

?????文件???????1577??2012-07-02?20:39??PDCCH\de_modulate_PDCCH.m

?????文件???????2091??2012-07-02?20:39??PDCCH\de_rate_match_PDCCH.m

?????文件???????1409??2012-07-02?20:39??PDCCH\de_scramble_PDCCH.m

?????文件???????1836??2012-07-02?20:39??PDCCH\main_PDCCH_coding.m

?????文件???????1554??2012-07-02?20:39??PDCCH\main_PDCCH_decoding.m

?????文件????????741??2012-07-02?20:39??PDCCH\modulation_QPSK_PDCCH.m

?????文件????????192??2012-07-02?20:39??PDCCH\nanPosition.mat

?????文件???????2179??2012-07-02?20:39??PDCCH\rate_match_PDCCH.m

?????文件???????1136??2012-07-16?11:24??PDCCH\scramble_PDCCH.asv

?????文件???????1136??2012-07-02?20:39??PDCCH\scramble_PDCCH.m

?????文件????????631??2012-07-10?17:05??PDCCH\tail_coding_PDCCH.asv

?????文件????????631??2012-07-02?20:39??PDCCH\tail_coding_PDCCH.m

?????文件???????2762??2012-07-02?20:39??PDCCH\tail_decoding_PDCCH.m

?????文件????????925??2012-07-02?20:39??PDCCH\tail_next.m

?????目錄??????????0??2012-07-23?09:22??PDCCH

-----------?---------??----------?-----??----

????????????????29212????????????????????20