%求兩個向量個個元素的夾角??-pi~pi
function?Y=ang（x1x2）
a=angle（x1）-angle（x2）;
location=find（a>pi）;
a（location）=a（location）-pi*2;
location=find（a<-pi）;
a（location）=a（location）+pi*2;???
Y=cos（a）;

?屬性????????????大小?????日期????時間???名稱
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?????文件????????201??2011-08-08?09:35??ACE\ang.m

?????文件?????????67??2011-08-08?09:35??ACE\conjugation.m

?????文件???????1897??2011-08-08?09:35??ACE\cons2_test.m

?????文件????????815??2011-08-08?09:35??ACE\cons_test.m

?????文件????????713??2011-08-08?09:35??ACE\DEOFDM.m

?????文件????????503??2011-08-08?09:35??ACE\deqpsk.m

?????文件????????386??2011-08-08?09:35??ACE\findmax.m

?????文件????????356??2011-08-08?09:35??ACE\IFFTrevise.m

?????文件???????8730??2011-08-08?09:35??ACE\Main.m

?????文件????????244??2011-08-08?09:35??ACE\myawgn.m

?????文件????????568??2011-08-08?09:35??ACE\myFFT.m

?????文件????????119??2011-08-08?09:35??ACE\myIFFT.m

?????文件????????725??2011-08-08?09:35??ACE\OFDM.m

?????文件????????186??2011-08-08?09:35??ACE\pilot_delete.m

?????文件????????319??2011-08-08?09:35??ACE\pilot_insert.m

?????文件????????354??2011-08-08?09:35??ACE\QPSK.m

?????目錄??????????0??2011-08-11?15:09??ACE

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????????????????16183????????????????????17