%%?概率域的BP算法?2012.5.8??兩種方法均可?way1去掉為0項?way2采用稀疏矩陣
%%?初始化
clear
clc
load?G.mat
load?H2.mat
H=H2;
M=2;
%??load?G_225.mat
%??load?H2_225.mat
%?load?Margulis_2640_1320_3
%?H2=H;
%?way=2;?%?方法選擇開關
Num=1;%?數據量
iterative_num=5;%?迭代次數

EbN0=1;%信噪比

n=size（G2）;
k=size（G1）;
m=size（H21）;%?校驗矩陣的行數
%?if?way==1
%?else?break;
%
%?????for?i=1:n
%?????????C（i:）?=?find（H2（:i）==1）;%?初始化與變量節點相連的校驗節點?C
%?????end
%?????for?j=1:m
%?????????R（j:）?=find（H2（j:）==1）;%?初始化與校驗節點相連的變量節點的集合R
%?????end
%?end

source_I=round（rand（1k*Num））;
source_Q=round（rand（1k*Num））;

source_matr_I=reshape（source_IkNum）‘;
source_matr_Q=reshape（source_QkNum）‘;
Y_I=mod（source_matr_I*double（G）2）;
%?Y_Q=mod（source_matr_Q*double（G）2）;
Y_Q=Y_I;
Y_I_arr=reshape（Y_I‘1size（Y_I1）*size（Y_I

?屬性????????????大小?????日期????時間???名稱
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?????文件???????1110??2012-12-13?10:39??QPSK\code.mat

?????文件??????27293??2012-04-17?17:23??QPSK\G.mat

?????文件???????2084??2012-04-18?20:53??QPSK\G_225.mat

?????文件?????444022??2012-11-10?17:46??QPSK\G_4283_5256.mat

?????文件??????22175??2012-04-17?17:23??QPSK\H2.mat

?????文件???????1866??2012-04-18?20:53??QPSK\H2_225.mat

?????文件??????34077??2012-11-10?17:46??QPSK\H2_4283_5256.mat

?????文件??????24589??2012-12-13?10:40??QPSK\llr.mat

?????文件???????2556??2012-12-17?21:59??QPSK\main.m

?????文件???????2554??2012-06-11?20:27??QPSK\main2.m

?????文件???????2335??2012-12-27?22:28??QPSK\main_v3.m

?????文件???????4859??2012-11-26?21:14??QPSK\qpsk_uncoded.fig

?????文件???????1705??2012-12-27?22:36??QPSK\soft_demap_qpsk.m

?????文件???????2507??2012-06-11?15:29??QPSK\SPA_decoder.m

?????目錄??????????0??2014-12-24?19:43??QPSK

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???????????????573732????????????????????15