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LBM方法,多弛豫時間的重力驅動poiseuille流的matlab代碼

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代碼片段和文件信息

%GLBE?based?incompressible?MRT?model?for?gravity?
%driven?fluid?flow?simulation?in?a?parallel?channel.
%
%D2Q9:?2D-?9?velocity?model

%lx?is?length?of?domain?and?ly?is?width.?
%g?is?applied?gravity?in?X-direction
%Copyright:?Shadab?Anwar?Florida?International?University?USA.
%sanwa001@fiu.edu
%*********************************************************************
clear?all;close?all;
wa(9)=4/9;wa(1:4)=1/9;wa(5:8)=1/36;
lx=8;ly=33;?rho0_in=1.0001;?rho0_out=1.;
u=zeros(lylx2);?g=?1e-04;
u_pois=zeros(1ly);?f=zeros(lylx9);
ftemp=zeros(lylx9);rho=ones(lylx);
u(::1)=0.0041;
M=[???111111111;
?????-1-1-1-12222-4;
?????-2-2-2-211114;
??????10-101-1-110;
?????-20201-1-110;
??????010-111-1-10;
??????0-20211-1-10;
??????1-11-100000;
??????00001-11-10;
];

s=[0-1.64-1.540-1.90-1.9-1.-1.];?%?relaxation?parameters
%s(9)?controls?the?kinematic?viscosity?and?hence?the?Reynolds?number.

ts=300;

a2=-8;a3=4;c1=-2;g1=2/3;g3=2/3;g2=18;g4=-18;??%?a3?and?g4?are?free?to?tune
e(1:)=[10-101-1-110];?%ex
e(2:)=[010-111-1-10];?%ey

%i=10;j=5;
%rho=1;

?tau(1)=-1/s(9);?
?nu=(1/3)*(tau(1)-0.5);
?ni=ly;
?%dpdl=(1/3)*(1e-04)/lx;
??mm=1;

for?i=-(ni-1)/2:(ni-2)/2
u_pois(mm)=(g/(2*nu))*(((ni-2)/2)^2-i^2);
%u_pois(mm)=(dpdl/(2*nu))*(((ni-2)/2)^2-i^2);
u_pois(1)=0.0;
mm=mm+1;
end
u_pois(mm)=0.0;

%initialize?f‘s
for?i=1:lx
????for?j=1:ly

u(ji1)=u_pois(j);

jx=u(ji1);
jy=u(ji2);

m_eq(1)?=?rho(ji);?%density
m_eq(2)?=?(a2/4)*rho(ji)?+?(1/6)*g2*(jx^2+jy^2);??%energy
m_eq(3)?=?(a3/4)*rho(ji)?+?(1/6)*g4*(jx^2+jy^2);??%energy?square
m_eq(4)?=?jx;?%momentum?in?x-dir
m_eq(5)?=?(1/2)*c1*jx;?%energy?flux?in?x-dir
m_eq(6)?=?jy;?%momentum?in?y-dir
m_eq(7)?=?(1/2)*c1*jy;?%energy?flux?in?y-dir
m_eq(8)?=?(3/2)*g1*(jx^2?-?jy^2);?%diagonal?comp?of?stress?tensor
m_eq(9)?=?(3/2)*g3*jx*jy;??%off?diagonal?comp?of?stress?tensor
????????????
f(ji:)=inv(M)*(m_eq‘);
????end
end

????????F(9)?=?3*wa(9)*(?e(19)*g?);
????????for?a=1:8
?????????????F(a)=3*wa(a)*(?e(1a)*g?);??%F?is?applied?body?force?(gravity)
????????end
for?t=1:ts
????t
%Macroscopic?variable
for?i=1:lx
????for?j=1:ly
????????
????????rho(ji)=sum(f(ji:));
????????u(ji:)=0.;
????????
?????????for?a=1:9
????????u(ji1)?=?u(ji1)?+?e(1a)*f(jia);
????????u(ji2)?=?u(ji2)?+?e(2a)*f(jia);
??????????end
??????????
??????u(ji1)=?u(ji1)/rho(ji);
??????u(ji2)=?u(ji2)/rho(ji);
??
f_pre=ones(91);f_post=ones(91);

%Compute?Meq?or?moment?of?feq
jx=u(ji1);
jy=u(ji2);

m_eq(1)?=?rho(ji);?%density
m_eq(2)?=?(a2/4)*rho(ji)?+?(1/6)*g2*(jx^2+jy^2);??%energy
m_eq(3)?=?(a3/4)*rho(ji)?+?(1/6)*g4*(jx^2+jy^2);??%energy?square
m_eq(4)?=?rho(ji)*jx;?%momentum?in?x-dir
m_eq(5)?=?(1/2)*c1*jx;?%energy?flux?in?x-dir
m_eq(6)?=?rho(ji)*jy;?%momentum?in?y-dir
m_eq(7)?=?(1/2)*c1*jy;?%energy?flux?in?y-dir
m_eq(8)

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????4724??2013-04-28?18:45??Untitled.m

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