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資源簡介

基本思想:首先任意選取K個聚類中心,按最小距離原則將各模式分配到K類的某一類; 不斷計算聚類中心和調整各模式的類別,最終使各模式到其判屬類別中心的距離平方之和最小。

資源截圖

代碼片段和文件信息

clear;
clc;
x=[0321546567];
y=[0821383445];
????ca1(1)=x(4);%center?of?first?cluster
????cb1(1)=y(4);
????ca2(1)=x(2);%center?of?second?cluster
????cb2(1)=y(2);
????ca3(1)=x(9);%center?of?third?cluster
????cb3(1)=y(9);
????d1=0;d2=0;d3=0;Z=zeros(13);d=0;
????suma1=ca1(1);sumb1=cb1(1);
????suma2=ca2(1);sumb2=cb2(1);
????suma3=ca3(1);sumb3=cb3(1);
????n1=1;n2=1;n3=1;
????k=1;
????t=0;
????cluster=zeros(110);
????ra1=0.0;
????rb1=0.0;
????ra2=0.0;
????rb2=0.0;
????ra3=0.0;
????rb3=0.0;
while?t==0
????for?i=1:10
????d1=(x(i)-ca1(k))^2+(y(i)-cb1(k))^2;
????d2=(x(i)-ca2(k))^2+(y(i)-cb2(k))^2;
????d3=(x(i)-ca3(k))^2+(y(i)-cb3(k))^2;
????Z=[d1d2d3];
????d=min(Z);
????if?d==d1
????????suma1=suma1+x(i);
????????sumb1=sumb1+y(i);
????????n1=n1+1;
????????cluster(i)=1;
????elseif?d==d2
????????suma2=suma2+x(i);
???

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