資源簡(jiǎn)介
此文件為RSA算法的加解密,使用Matlab語(yǔ)言

代碼片段和文件信息
function?RSA2=decod(miwen)
miwen=input(‘輸入密文:‘);
?Q=input(‘Q=(p-1)(q-1)=‘);
?e=input(‘e=‘);
?n=input(‘n=‘);
?k=0;
?while?mod(k*Q+1e)~=0
?????k=k+1;
?end
?d1=(k*Q+1)/e;??????%計(jì)算e的模逆
?disp(d1)
?l1=length(miwen);
b=dec2bin(d1);
l2=length(b);
for?j=1:1:l1
????c=0;
???d=1;
for?i=1:1:l2
?????c=2*c;
?????d=mod(d*dn);
??if?b(i)==‘1‘
?????c=c+1;
?????d=mod(d*miwen(j)n);
??end
end??????????
if?miwen(j)>=97&&miwen(j)<=122
minwen(j)=char(mod(d26)+97);??????????%密文是小寫(xiě)字母
elseif?miwen(j)>=65&&miwen(j)<=90
????minwen(j)=char(mod(d26)+65);???????%密文是大寫(xiě)字母
else??minwen(j)=d;?????????%密文是數(shù)字
end
end
disp(minwen)
?
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件????????667??2009-05-10?09:50??RSA\decod.m
?????文件???????1197??2009-05-06?10:07??RSA\encod.m
?????文件?????????39??2009-05-16?19:45??RSA\說(shuō)明.txt
?????目錄??????????0??2009-05-16?19:44??RSA
-----------?---------??----------?-----??----
?????????????????1903????????????????????4
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