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資源簡介

隨著物流的發展,多倉儲機器人的發展越來越迅速,多機器人任務分配的優劣決定著多機器人系統運行效率,目前應用最多任務分配算法是基于市場機制的拍賣算法。

資源截圖

代碼片段和文件信息

clc;
clear;
close?all;
n?=?10;
map=ones(n);
cmap?=?[1?1?1;?...%??1?-?white?-?空地
????????0?0?0;?...%?2?-?black?-?障礙?
????????1?0?0;?...%?3?-?red?-?已搜索過的地方
????????0?0?1;?...%?4?-?blue?-?下次搜索備選中心?
????????0?1?0;?...%?5?-?green?-?起始點
????????1?1?0;...%?6?-?yellow?-??到目?標點的路徑?
???????1?0?1];%?7?-?-??目標點?
colormap(cmap);
%robot=[246];
%?robot1=21;
%?robot2=41;
%?robot3=61;
%?map(robot1)=3;
%?map(robot2)=3;
%?map(robot3)=3;
robot1=2;
robot2=4;
robot3=6;
map(robot1)=3;
map(robot2)=3;
map(robot3)=3;
[r1xr1y]=ind2sub([nn]robot1);
[r2xr2y]=ind2sub([nn]robot2);
[r3xr3y]=ind2sub([nn]robot3);
%[rxry]=ind2sub([nn]robot);
%mrobot=[rx‘ry‘];
%?[r2xr2y]=ind2sub([nn]robot(2));
%?[r3xr3y]=ind2sub([nn]robot(3));
h=10;
%b=randperm(90a)+10;?%產生1個1到100之間隨機的整數
%b=[15192545275678983451];
%[bxby]=ind2sub([nn]b‘);
%taskx=[bxby];
sum_cost=zeros(51);
%[e1f1]=size(mrobot);
image(1.51.5?map);?
set(gca‘YDir‘‘normal‘);
grid?on;?
%hold?on;
tic
i=1;
j2=1;
while?h<=10;
??%??b=randperm(90h)+10;?%產生1個1到100之間隨機的整數
??%?b=?[43????38????28????98????22????94????46????19????23????11????57????34????63????42????27????83????72????78????97????33????35????37????61?24????29????40????58????88????52????48????76????82????49????47????91????75????17????30????86????80????15????70????50????84????26????66??93????44????99????53];
????map(b)=4;
????[bxby]=ind2sub([nn]b‘);
????taskx=[bxby];
????cost=[];
????s1=[];
????s2=[];
????s3=[];
????j2=1;
??while?j2<=50;
????[ef]=size(taskx);
??%??[e1f1]=size(mrobot);
????m1=[];
????m2=[];
????m3=[];
????j=1;
????while?j<=e
?????%?for?j1=1:e1
????????if(isempty(s1))
???????????cost1=abs(r1x-taskx(j1))+abs(r1y-taskx(j2));
????????else
???????????cost1=abs(s1(end1)-taskx(j1))+abs(s1(end2)-taskx(j2));?
????????end
????????m1=[m1;cost1];
?????????if(isempty(s2))
????????????cost2=abs(r2x-taskx(j1))+abs(r2y-taskx(j2));
?????????else
????????????cost2=abs(s2(end1)-taskx(j1))+abs(s2(end2)-taskx(j2));
?????????end
?????????m2=[m2;cost2];
?????????if(isempty(s3))
????????????cost3=abs(r3x-taskx(j1))+abs(r3y-taskx(j2));
?????????else
????????????cost3=abs(s3(end1)-taskx(j1))+abs(s3(end2)-taskx(j2));
?????????end
?????????m3=[m3;cost3];
?????????j=j+1;
????end
????a=min(m1);
????b=min(m2);
????c=min(m3);
????m=[a;b;c];
????[xy]=min(m);
????sum_cost(i)=sum_cost(i)+x;
????cost=[cost;x];
????if(y==1)
????????d=find(m1==x);
????????s1=[s1;taskx(d(1):)];
????????taskx(d(1):)=[];
????end
????if(y==2)
????????d=find(m2==x);
????????
????????s2=[s2;taskx(d(1):)];
?????????taskx(d(1):)=[];
????end
????if(y==3)
????????d=find(m3==x);
????????s3=[s3;taskx(d(1):)];
?????????taskx(d(1):)=[];
????end?
????j2=j2+1;
??end
??h=h+10;
??i=i+1;
end
%?clear
%?h=10:10:50;
%?y=[?46?124?191?264?284];
%?y2=[?29??44??50?66?80?];
%?plot(?hy‘-ob‘‘linewidth‘2);
%?grid?on;
%?hold?on;
%?plot(?hy2‘-xr‘‘linewidt

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2019-04-01?17:45??任務分配算法\
?????目錄???????????0??2019-03-28?11:48??任務分配算法\html\
?????文件???????12025??2019-03-28?11:48??任務分配算法\html\task4.html
?????文件????????1912??2019-03-28?11:48??任務分配算法\html\task4.png
?????文件????????9110??2019-03-28?11:48??任務分配算法\html\task4_01.png
?????文件???????12979??2019-03-28?11:48??任務分配算法\html\task4_02.png
?????文件???????11740??2019-03-28?11:48??任務分配算法\html\task4_03.png
?????文件????????4308??2019-03-18?10:05??任務分配算法\task.m
?????文件?????????967??2019-04-01?19:23??任務分配算法\task1.m
?????文件????????1408??2019-03-21?15:24??任務分配算法\task2.m
?????文件????????4437??2019-03-19?09:33??任務分配算法\task3.m
?????文件????????2869??2019-04-01?17:34??任務分配算法\task4.m
?????文件????????2313??2019-03-21?10:06??任務分配算法\task5.m
?????文件????????3225??2019-03-29?16:10??任務分配算法\task6.m
?????文件????????1183??2019-03-29?10:35??任務分配算法\task7.m

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