資源簡介
給了一個H2/H∞混合控制例程,里面有源程序及仿真模型框圖

代碼片段和文件信息
echo?off
clc
A=[0?1;-0.6826?-1.7628];
B=[0;1];
C=[0.0368?0];
E=[1;1];
U=[0.3?0;?0?0.3];
V=[1?0;?0?1];
F=eye(2);
%alpha=0.1;
T=0.3;
[GH]=c2d(ABT);
M=(expm(A*T)-eye(2))*inv(A)*E;
%Gq=((eye(2)+A*T)+F*(eye(2)+A*T)*inv(F))/2.0;
Hq=expm(A*T)*(T*eye(2)-inv(A))*inv(A)+inv(A)*inv(A);
%Hq=0;
%Tp=0.01*T;
%for?i=0:100
%??Hq=Hq+((eye(2)+A*i*Tp)+F*(eye(2)+A*i*Tp)*inv(F))*i*Tp/2.0;
%end
Mq=Hq;
%Mq=0;
%Tp=0.01*T;
%for?i=0:100
?%?Mq=Mq+((eye(2)+A*i*Tp)+F*(eye(2)+A*i*Tp)*inv(F))*i*Tp/2.0;
?%end
%deltaG=alpha*G*F*T;
%deltaH=alpha*Hq*F*B;
%deltaM=Mq*U*U‘*F*E;
const1=1;
const2=0.1;
W=G*U*U‘*G‘+Hq*U*U‘*Hq‘+Mq*U*U‘*Mq‘;
gama=10;
%for?i=1:length(gama)
????
setlmis([]);
S=lmivar(1[1?1]);
Q=lmivar(1[2?1]);
Y=lmivar(2[1?2]);
%1st?LMI
lmiterm([1?1?1?Q]-11);
lmiterm([1?2?1?0]0);
lmiterm([1?3?1?Q]G1);
lmiterm([1?3?1?Y]H1);
lmiterm([1?4?1?Q]1V*T);
lmiterm([1?5?1?Y]V*B1);
lmiterm([1?6?1?Q]C1);
lmiterm([1?7?1?0]0);
lmiterm([1?2?2?0]-gama^2);
%lmiterm([1?2?2?0](1/const1)*E‘*E);
lmiterm([1?3?2?0]M);
lmiterm([1?4?2?0]0);
lmiterm([1?5?2?0]0);
lmiterm([1?6?2?0]0);
lmiterm([1?7?2?0]V*E);
lmiterm([1?3?3?Q]-11);
lmiterm([1?3?3?0]const1*W);
lmiterm([1?4?3?0]0);
lmiterm([1?5?3?0]0);
lmiterm([1?6?3?0]0);
lmiterm([1?7?3?0]0);
lmiterm([1?4?4?0]-const1);
lmiterm([1?5?4?0]0);
lmiterm([1?6?4?0]0);
lmiterm([1?7?4?0]0);
lmiterm([1?5?5?0]-const1);
lmiterm([1?6?5?0]0);
lmiterm([1?7?5?0]0);
lmiterm([1?6?6?0]-1);
lmiterm([1?7?6?0]0);
lmiterm([1?7?7?0]-const1);
%2nd?LMI
lmiterm([2?1?1?S]-11);
lmiterm([2?2?1?0]M);
lmiterm([2?3?1?0]V*E);
lmiterm([2?2?2?Q]-11);
lmiterm([2?2?2?0]const2*Mq*Mq‘);
lmiterm([2?3?2?0]0);
lmiterm([2?3?3?0]-const2);
%3rd?LMI
lmiterm([-3?1?1?Q]11);
%4th?LMI
%lmiterm([-4?1?1?S]11);
lmisys=getlmis;
n=decnbr(lmisys);
c=zeros(n1);
for?j=1:n
????[Sj]=defcx(lmisysjS);
????c(j)=trace(S);
end
%V1=defcx(lmisys1SYQ);
%c=[1?0?0?0?0?0]‘;
%x=[S?0?0?0?0?0]‘;
%c=mat2dec[lmisys1];
[coptxopt]=mincx(lmisysc[0?0?0?0?0]);
Sf=dec2mat(lmisysxoptS)
Yf=dec2mat(lmisysxoptY);
Qf=dec2mat(lmisysxoptQ);
K=Yf*inv(Qf)
%trace((M+deltaM)‘*inv(Qf)*(M+deltaM))
%end
L=eig(A+B*K)
Ec=L(1)*L(2)/0.0368
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件??????20656??2005-12-18?20:43??H2和H無窮混合控制\gama_H2.fig
?????文件??????28400??2005-12-19?13:46??H2和H無窮混合控制\gama_H21.fig
?????文件??????15931??2005-12-19?10:57??H2和H無窮混合控制\H2_Hinf.mdl
?????文件??????18536??2005-12-30?17:11??H2和H無窮混合控制\h2_hinf_simulation.mdl
?????文件???????2266??2005-12-30?16:41??H2和H無窮混合控制\shiyan_H2_Hinf.m
?????文件???????1906??2005-12-15?13:43??H2和H無窮混合控制\simu_K.asv
?????文件???????1917??2005-12-15?13:44??H2和H無窮混合控制\simu_K.m
?????文件???????1669??2006-01-16?11:57??H2和H無窮混合控制\simu_KUV.asv
?????文件???????2217??2005-12-19?10:51??H2和H無窮混合控制\simu_KUV.m
?????文件??????31400??2005-12-19?19:04??H2和H無窮混合控制\turb_unW.fig
?????文件??????33848??2005-12-19?19:12??H2和H無窮混合控制\turb_W.fig
?????文件??????31504??2005-12-19?19:03??H2和H無窮混合控制\unW_unturb.fig
?????目錄??????????0??2009-06-11?19:08??H2和H無窮混合控制
?????文件????????183??2009-02-02?09:47??Matlab中文論壇--助努力的人完成畢業設計.url
?????文件???????3543??2009-02-01?16:19??使用幫助:新手必看.htm
-----------?---------??----------?-----??----
???????????????193976????????????????????15
評論
共有 條評論