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資源簡介

網上只有水平或豎直情況的矩形haar-like feature,而這個代碼是傾斜情況下,haar-like feature,雖然代碼簡單,但是要弄懂其中算法要花不少時間。為了節省同道中人的時間,我將這個代碼共享。感謝Rainer Lienhart的論文。

資源截圖

代碼片段和文件信息

%generate_RSAT.m
%2013.11.16
%by:?zhou?dongao
%Function:
????%Caculate?rotate?45?degrees?summed?area?table
%This?code?is?based?on?the?article?of?Rainer?Lienhart‘s?algorithm
%See?the?pdf:
%http://www.multimedia-computing.de/mediawiki//images/5/52/MRL-TR-May02-revised-Dec02.pdf

%All?of?the?parameters‘?names?are?cited?from?Rainer‘s?article
%Attention:?Please?read?the?article?first!?It‘s?very?useful?to?understand
%this?code

function?[RSAT]?=?generate_RSAT(?image?)
%test
%?clear?all?close?allclc
%?image?=?double(imread(‘n01-x.PNG‘));
%?figure?imshow(image)?title(‘Input?image‘);

%RSAT:?rotate?45?degree?summed?area?table?which?size?equal?to?image‘s?
%image:?input?image
image?=?double(image);
[HW]?=?size(image);%width(W)?is?columnheight(H)?is?row?of?the?input?image

%expand?the?image‘s?size?by?comple?makeup?of?0
%a?row?and?two?column?are?increased?which?valued?0
RSAT_ex?=?double(zeros(H+2?W+2));%initialize?expanded?RSAT?and?named?RSAT_ex
image_ex?=?[zeros(1W);?image];
%image_ex?=?[zeros(H+12)?image_ex];
for?j?=?3?:?H+2??????????%from?top?to?bottom
????for?i?=?2?:?W+1??????%from?left?to?right
????????RSAT_ex(j?i)?=?RSAT_ex(j-1?i-1)?+?RSAT_ex(j-1?i+1)...
????????????-RSAT_ex(j-2?i)?+?image_ex(j-2?i-1)?+?image_ex(j-1?i-1);%see?algorthm?of?Rainer
????end
end


%?for?j?=?3?:?H+1
%?????for?i?=?2?:?W+1
%?????????RSAT_ex(i?j)?=?RSAT_ex(i-1?j-1)?+?RSAT_ex(i+1?j-1)...
%?????????????-RSAT_ex(i?j-2)?+?image_ex(i?j-1)?+?image_ex(i?j);
%?????end
%?end

RSAT?=?RSAT_ex(3:H+2?2:W+1);%excluding?zeros?to?make?it‘s?size?equal?to?image‘s


?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2013-11-16?16:24??rotate_haar_like\
?????文件????????1610??2013-11-16?16:20??rotate_haar_like\generate_RSAT.m
?????文件?????????928??2013-11-16?16:20??rotate_haar_like\RRecSum.m
?????文件?????????756??2013-11-16?16:17??rotate_haar_like\test.m

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