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資源簡介

王錫凡版三機九節(jié)點的暫態(tài)穩(wěn)定性仿真程序,包括計凸極效應還是不計凸極效應的仿真

資源截圖

代碼片段和文件信息

clc;clear;
n1=9;n2=9;
B1=load(‘b1.txt‘‘ascii‘);
B2=load(‘b2.txt‘‘ascii‘);
m=0;r=0;
for?i=1:n1
????if?B1(i8)==1
????????m=m+1;
????end
end
r=n1-m-1;
e=B1(1:n12);f=B1(1:n13);
ps=B1(1:n14)-B1(1:n16);
qs=B1(1:n15)-B1(1:n17);

Y=zeros(n1);
for?j=1:n2
??????p=B2(j2);q=B2(j3);J=zeros(2*n1);
??????Y(pq)=-1./((B2(j4)+1i*B2(j5))*B2(j7));
??????Y(qp)=Y(pq);
??????Y(pp)=Y(pp)+1/(B2(j4)+1i*B2(j5))+1i*B2(j6);
??????Y(qq)=Y(qq)+1/((B2(j4)+1i*B2(j5))*B2(j7)^2)+1i*B2(j6);
end
%導納矩陣Y
H1=zeros(n1);N1=zeros(n1);J1=zeros(n1);L1=zeros(n1);
G=real(Y);B=imag(Y);
dp(1:(n1-1))=1;dq(1:m)=1;dx(1:(2*m+r))=1;
while?(abs(max(dp)>=1.0e-5)|abs(max(dq)>=1.0e-5)|abs(max(dx(1:(m+r)))>=1.0e-5)|abs(max(dx((m+r+1):(2*m+r)).*e(1:m))>=1.0e-5))
for?i=1:n1
????for?j=1:n1
????????si(ij)=sin(f(i)-f(j));
????????co(ij)=cos(f(i)-f(j));
????????if?i==j
????????????H1(ij)=e(i)^2*B(ii)+qs(i);
????????????N1(ij)=-e(i)^2*G(ii)-ps(i);
????????????J1(ij)=e(i)^2*G(ii)-ps(i);
????????????L1(ij)=e(i)^2*B(ii)-qs(i);
????????else
????????????H1(ij)=-e(i)*e(j)*(G(ij)*si(ij)-B(ij)*co(ij));?
????????????N1(ij)=-e(i)*e(j)*(G(ij)*co(ij)+B(ij)*si(ij));?
????????????J1(ij)=e(i)*e(j)*(G(ij)*co(ij)+B(ij)*si(ij));
????????????L1(ij)=-e(i)*e(j)*(G(ij)*si(ij)-B(ij)*co(ij));
????????end??????
????end
end
H=H1(2:n12:n1);
N=N1(2:n1r+2:n1);
J=J1(r+2:n12:n1);
L=L1(r+2:n1r+2:n1);
J=[H?N;J?L];
%雅克比矩陣J
?for?i=2:n1
????a(i)=0;b(i)=0;
????for?j=1:n1
????????a(i)=a(i)+e(j)*(G(ij)*co(ij)+B(ij)*si(ij));
????????if?i>=(r+2)
????????b(i)=b(i)+e(j)*(G(ij)*si(ij)-B(ij)*co(ij));
????????end
?????end
????dp(i-1)=ps(i)-e(i)*a(i);
????if?i>=(r+2)
???????dq(i-(r+1))=qs(i)-e(i)*b(i);
????end
end
F=[dp‘;dq‘];
dx=-J\F;
f(2:n1)=f(2:n1)+dx(1:(m+r));
e1=e((r+2):n1)+dx((m+r+1):(2*m+r)).*e((r+2):n1);
e2=e(1:(r+1));
e=[e2;e1];
end
%disp(‘e=‘);disp(e‘);
%disp(‘單位:度?f=‘);disp(f‘*180/3.1415926)
%求出各節(jié)點電壓幅值及相角
????a=0;
?for?i=1:n1
????a=a+conj(Y(1i))*(e(i)*cos(f(i))-1i*e(i)*sin(f(i)));
?end
????a=a*(e(1)*cos(f(1))+1i*e(1)*sin(f(1)));
%disp(‘平衡節(jié)點P+jQ=‘);disp(a);

%初值計算
?for?j=1:n1
?????s(j)=0;
?????for?i=1:n1
?????s(j)=s(j)+conj(Y(ji))*(e(i)*cos(f(i))-1i*e(i)*sin(f(i)));
?????end
?????s(j)=s(j)*(e(j)*cos(f(j))+1i*e(j)*sin(f(j)));
?end
?Y1=conj(-s)./(e‘.^2);
?%disp(‘S=‘);disp(s);
?
?Ra=[0?0?0];X_d=[0.0608?0.1198?0.1813];Xq=[0.0969?0.8645?1.2578];
?%Xq=X_d;%不計凸極效應
?v=e.*cos(f)+1i*e.*sin(f);
?for?i=1:3
?I(i)=conj(s(i)/(e(i)*cos(f(i))+1i*e(i)*sin(f(i))));
?EQ(i)=e(i)*cos(f(i))+1i*e(i)*sin(f(i))+(Ra(i)+1i*Xq(i))*I(i);
?EQx(i)=real(EQ(i));EQy(i)=imag(EQ(i));
?delta(i)=atan(EQy(i)/EQx(i));
?end
?%disp(‘delta=‘);disp(delta*180/3.1415926);
?for?i=1:3
?????Vx(i)=e(i)*cos(f(i));?Vy(i)=e(i)*sin(f(i));
?????Vdq=[sin(delta(i))?-cos(delta(i));cos(delta(i))?sin(delta(i))]*[Vx(i);Vy(i)];
?????Vd(i)=Vdq(1);Vq(i)=Vdq(2);
?????Ix(i)=real(I(i));Iy(i)=imag(I(i));
?????Idq=[sin(delta(i))?-cos(delta(

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----

?????文件????????814??2014-01-03?16:43??暫態(tài)\b1.txt

?????文件????????611??2014-01-03?16:51??暫態(tài)\b2.txt

?????文件???????6478??2014-12-07?21:39??暫態(tài)\zantai.m

?????目錄??????????0??2014-12-07?21:39??暫態(tài)

-----------?---------??----------?-----??----

?????????????????7903????????????????????4


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