資源簡介
X 0 1 4 9 16 25 36 49 64
Y 0 1 2 3 4 5 6 7 8
三次樣條,復合梯形公式,復合辛普森公式,龍貝格公式求積分,數值分析第5版李慶揚
代碼片段和文件信息
#include
#include
using?namespace?std;
main()
{
????double?x[9]={01491625364964};
????double?y[9]={012345678};
????double?t?s?matrix[9][10]?h[8]?u[9]?v[8]?xishu[8][4];
????int?i?j;
????for(i=0;i<=8;i++){
????for(j=0;j<=9;j++){
????if(i==j)
????matrix[i][j]=2;
????else
????matrix[i][j]=0;
????}
}
????for(i=0;i<=7;i++){
????h[i]=x[i+1]-x[i];
????}
????u[0]=u[8]=1;
????for(i=1;i<=7;i++){
????u[i]=h[i-1]/(h[i-1]+h[i]);
????}
????v[0]=1;
????for(i=1;i<=7;i++){
????v[i]=h[i]/(h[i-1]+h[i]);
????}
????matrix[0][9]=100;
????for(i=1;i<=7;i++){
????matrix[i][9]=6*((y[i]-y[i+1])/(x[i]-x[i+1]))/(h[i-1]+h[i]);
????}
????matrix[i][9]=6*(1.0/16.0-(y[i-1]-y[i])/(x[i-1]-x[i]))/h[i-1];
????for(j=0;j<=8;j++){
????????for(i=0;i<=8;i++)
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????1822??2014-04-27?23:19??數值分析2\三次樣條.cpp
?????文件?????195986??2014-04-27?23:50??數值分析2\實驗報告.doc
?????文件????????743??2014-04-27?23:14??數值分析2\梯形.cpp
?????文件????????805??2014-04-27?23:25??數值分析2\辛普森.cpp
?????文件???????1276??2014-04-27?23:37??數值分析2\龍貝格.cpp
?????目錄??????????0??2014-04-27?23:50??數值分析2
-----------?---------??----------?-----??----
???????????????200632????????????????????6
- 上一篇:DHCP服務器的安裝實驗報告.doc
- 下一篇:PCS7 OS SET
評論
共有 條評論