%?常用的CEC基準測試函數

function?result?=?fitness（xD）?
?sum=0;

%?%?Sphere函數?[-100100]?min=0??（0000...）
%?for?d=1:D
%?????sum=sum+（x（d）^2）;
%?end
%?result=sum;
?
%?Quartic函數??[-1.281.28]?min=0?000000
for?d=1:D
????sum=sum+d*（x（d）^4）;
end?
result=sum;%+rand;

%?Schwefel‘‘s?Problem?2.22??[-1010]?00000
%?p=1;
%?for?d=1:D
%?????p=p*abs（x（d））;
%?????sum=sum+abs（x（d））+p;
%?end?%?
%?result=sum;

%?Rosenbrock函數?[-3030]?min=0??（1111...）
%?for?d=1:D-1
%?????sum=sum+100*（（x（d+1）-x（d）^2）^2）+（x（d）-1）^2;
%?end?
%?result=sum;

%Rastrigin函數??%[-5.125.12]?min=0?00000
%?for?d=1:D
%?????sum=sum+（x（d）^2）-10*cos（2*pi*x（d））+10;
%?end?
%?result=sum;
?
%?Griewank函數?%[-600600]?min=0?00000??X/30
%?p=0;
%?q=1;
%?for?d=1:D
%?????p=p+（x（d）^2）;
%?????q=q*（cos（x（d）/sqrt（d）））;
%?end?
%?sum=p/4000-q+1;
%?result=sum;

%?Ackley函數??%?[-3030]?min=0??00000
%?p=0;
%?q=0;
%?for?d=1:D
%?????p=p+x（d）^2;
%?????q=q+cos（2*pi*x（d））;
%?end?
%?sum=-20*exp（-0.2*sqrt（p/D））-exp（q/D）+exp（1）+20;
%?result=sum;

%Schwefel’s?problem?2.26?[-500500]?f（420.9687）=0?這是變式
%原式f（420.9687）=-418.9829*D
%?for?d=1:D
%?????if??x（d）>500
%?????????x（d）=500;
%?????end
%?????if??x（d）<-500
%?????????x（d）=-500;
%?????end
%?????sum=sum-x（d）*sin（sqrt（abs（x（d））））;
%?end?
%?result=418.9829*D+sum;

%?Generalized?Penalized?Function2?[-5050]?0??111111
%?sum1=0;?%a=5?k=100?m=4???
%?sum1=（sin（3*pi*（x（1））））^2+（x（D）-1）^2;
%?sum2=0;
%?for?d=1:D-1
%?????sum2=sum2+（（x（d）-1）^2）*（1+（sin（3*pi*（x（d+1））））^2）;
%?end
%?sum3=0;
%?for?d=1:D
%?????if?x（d）>5
%????????u（d）=100*（x（d）-5）^4;
%?????elseif?x（d）<-5
%????????u（d）=100*（-x（d）-5）^4;
%?????else
%????????u（d）=0;
%?????end
%?????sum3=sum3+u（d）;
%?end
%?sum=0.1*（sum1+sum2）+sum3;?
%?result=sum;

%??Step函數?[-100100]?000000??
%?for?d=1:D
%?????sum=sum+（round（x（d）+0.5））^2;
%?end?
%?result=sum;

%??Schaffer函數?屋脊函數?[-100100]?min=-1?0000
%此函數在距全局最優點大約3.14范圍內存在無窮多個局部極小將其包圍，并且函數強烈振蕩
%幾種ABC算法都得到了較好的結果
%?for?d=1:D
%?????sum=sum+（x（d）^2）;
%?end?
%?result=（（sin（sqrt（sum）））^2-0.5）/（1+0.001*sum）^2+0.5;?%+1了，min=0

%??Schwefel‘‘s?Problem?1.2?[-100100]?00000??效果都不好
%?p=0;
%?for?d=1:D
%?????p=p+x（d）;
%?????sum=sum+p^2;
%?end
%?result=sum;

%??Schwefel‘‘s?Problem?2.21?[-100100]?
%?p=abs（x（1））;
%?for?d=1:D
%?????p=max（abs（x（d））p）;
%?end?
%?result=p;

%??Step函數?[-100100]?000000?
%?for?d=1:D
%?????sum=sum+（round（x（d）+0.5））^2;
%?end?
%?result=sum;

%??Generalized?Penalized?Function1?[-5050]?
%?sum1=10*（sin（pi*（1+（x（1）+1）/4）））^2+（（x（D）+1）/4）^2;
%?sum2=0;
%?for?d=1:D-1
%?????sum2=sum2+（（（x（d）+1）/4）^2）*（1+10*（sin（pi*（1+（x（d+1）+1）/4）））^2）;
%?end
%?sum3=0;
%?for?d=1:D
%?????if?x（d）>10
%????????u（d）=100*（x（d）-10）^4;
%?????elseif?x（d）<-10
%????????u（d）=100*（-x（d）-10）^4;
%?????else
%????????u（d）=0;
%?????end
%?????sum3=sum3+u（d）;
%?end
%?sum=（pi*（sum1+sum2）/D）+sum3;?
%?result=sum;
end

?屬性????????????大小?????日期????時間???名稱
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?????文件?????876544??2017-12-13?21:38??PSO\CEC優化測試函數.pdf

?????文件???????3013??2019-04-21?14:44??PSO\fitness.m

?????文件???????2404??2019-04-21?14:43??PSO\PSO.m

?????目錄??????????0??2019-04-21?14:44??PSO

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???????????????881961????????????????????4