資源簡介
MIMO系統容量仿真 包括兩個部分 (1)仿真代碼 (2)仿真word文檔的說明 -MIMO system capacity simulation consists of two parts (1) simulation code (2) Simulation word description of the document

代碼片段和文件信息
x=[123456789102030];
y1=[2.11772.74283.08773.26123.34723.42983.52413.56813.59643.61743.75603.7899];
plot(xy1)
hold?on
y2=[3.44914.93095.99816.40756.60116.77306.98857.10107.20067.30697.61297.6546];
plot(xy2)
hold?on
y3=[5.01247.70149.518310.568211.115611.598711.948312.154712.363312.523713.089313.3259];
plot(xy3)
hold?on
y4=[6.606810.777313.773615.598716.567617.293417.772118.108818.357618.536019.279819.4907];
plot(xy4)grid?on
xlabel(‘發射天線數nT‘);
ylabel(‘容量/(bit/s/Hz)‘);
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????190??2010-10-07?10:14??11673397MIMOdesign\新建?文本文檔.txt
?????文件????????551??2005-06-03?22:57??11673397MIMOdesign\MIMO容量仿真程序\MIMO信道容量仿真\huitu.m
?????文件????????564??2005-06-02?01:22??11673397MIMOdesign\MIMO容量仿真程序\MIMO信道容量仿真\wo.m
?????文件????1109504??2007-10-29?11:15??11673397MIMOdesign\MIMO容量仿真程序\MIMO系統容量仿真說明\MIMO系統容量仿真說明.doc
?????目錄??????????0??2010-10-14?16:18??11673397MIMOdesign\MIMO容量仿真程序\MIMO信道容量仿真
?????目錄??????????0??2010-10-14?16:18??11673397MIMOdesign\MIMO容量仿真程序\MIMO系統容量仿真說明
?????目錄??????????0??2010-10-14?16:18??11673397MIMOdesign\MIMO容量仿真程序
?????目錄??????????0??2010-10-14?16:18??11673397MIMOdesign
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??????????????1111027????????????????????9
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