資源簡(jiǎn)介
給定任何網(wǎng)絡(luò)拓?fù)浣Y(jié)構(gòu)的導(dǎo)納矩陣都能被求解、、包括帶變壓器

代碼片段和文件信息
clear;clc;
format?compact
%?n=input(‘請(qǐng)輸入節(jié)點(diǎn)數(shù):n=‘);
%?pr=input(‘請(qǐng)輸入精度誤差:pr=‘);
%?Z=input(‘請(qǐng)輸入由各節(jié)點(diǎn)間阻抗形成的距陣:Z=‘);
%?B=input(‘請(qǐng)輸入由各節(jié)點(diǎn)直接對(duì)地的導(dǎo)納距陣:B=‘);
%?K=input(‘請(qǐng)輸入由節(jié)點(diǎn)間變壓器變比值:K=‘);
%?N=input(‘請(qǐng)輸入當(dāng)變壓器兩端節(jié)點(diǎn)對(duì)地等效導(dǎo)納值確定條件:N=‘);
%數(shù)據(jù)輸入環(huán)節(jié)%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
n=5;
pr=0.00001;
Z=[0?0.04+0.25i?0.1+0.35i?0?0;
???0.04+0.25i?0?0.08+0.30i?0.015i?0;
???0.1+0.35i?0.08+0.30i?0?0?0.03i;
???0?0.015i?0?0?0;
???0?0?0.03i?0?0];
B=[0.25i?0.5i?0.25i?0?0];
K=[1?1?1?1?1;
???1?1?1?1.05?1;
???1?1?1?1?1.05;
???1?1.05?1?1?1;
???1?1?1.05?1?1;];
N=[0?1?1?0?0];
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Y=zeros(n);C=zeros(n)%(經(jīng)變壓器變換后對(duì)地的等效導(dǎo)納);
A=zeros(n);D=zeros(1n)%(經(jīng)變壓器變換后總的對(duì)地導(dǎo)納);
H=zeros(1n)%(經(jīng)變壓器變換后節(jié)點(diǎn)間互導(dǎo)納);
for?i=1:n
????for?j=1:n
????????if?Z(ij)~=0
?????????A(ij)=1/Z(ij)
????????end
????????if?Z(ij)==0
??????????A(ij)=0
????????end
????end
end
for?i=1:n
????for?j=1:n
????????H(ij)=A(ij)/K(ij)
????????if?K(ij)==1
???????????C(ij)=0
????????end
????????if?K(ij)~=1
???????????if?N(i)==1
??????????????C(ij)=(1-K(ij))*H(ij)/K(ij)
???????????end
????????????if?N(i)==0
????????????????C(ij)=(K(ij)-1)*H(ij)
???????????end
????????end
????????Q=C(i:)?%(取C矩陣的某一行元素)
????????D(i)=sum(sum(Q))+B(i)
????end
end
for?i=1:n
????for?j=1:n
????????if?i~=j
????????????Y(ij)=-H(ij)
????????end
????????if?i==j
????????????E=H(i:)?%(取H矩陣的某一行元素)
????????????Y(ij)=sum(sum(E))+D(i)
????????end
????end
end???????%求導(dǎo)納距陣
disp(‘導(dǎo)距Y為:‘);
disp(Y)
????????????
?
???????
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件???????1715??2010-04-08?23:22??daonaijuzhentongyongchengxu.m
-----------?---------??----------?-----??----
?????????????????1715????????????????????1
評(píng)論
共有 條評(píng)論