資源簡(jiǎn)介
對(duì)輸入的圖像,用Roberts算子處理,找到目標(biāo)邊緣,達(dá)到分割的目的

代碼片段和文件信息
%%----sobel算子邊緣檢測(cè)分割-------
clc
clear;
Im=imread(‘catdog.jpg‘);?%讀取原圖像
grayImg=mat2gray(Im);?%實(shí)現(xiàn)圖像矩陣的歸一化操作
[mn]=size(grayImg);
newGrayImg=grayImg;???%為保留圖像的邊緣一個(gè)像素
robertsNum=0;?????????%經(jīng)Roberts算子計(jì)算得到的每個(gè)像素的值初始值為0
robertThreshold=0.2;??%設(shè)定閾值
?%進(jìn)行邊界提取
for?j=1:m-1
????for?k=1:n-1
????????robertsNum?=?abs(grayImg(jk)-grayImg(j+1k+1))?+?abs(grayImg(j+1k)-grayImg(jk+1));
????????if(robertsNum?>?robertThreshold)
????????????newGrayImg(jk)=255;
????????else
????????????newGrayImg(jk)=0;
????????end
????end
end
%結(jié)果輸出與保存
figureimshow(newGrayImg);
title(‘Roberts算子的處理結(jié)果‘);?
imwrite(newGrayImg‘result\Roberts.jpg‘);
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件??????26332??2018-12-13?14:42??Roberts\catdog.jpg
?????文件??????29723??2018-12-25?15:06??Roberts\result\Roberts.jpg
?????文件????????728??2018-12-25?15:06??Roberts\Roberts.m
?????目錄??????????0??2018-12-25?15:33??Roberts\result
?????目錄??????????0??2018-12-25?15:33??Roberts
-----------?---------??----------?-----??----
????????????????56783????????????????????5
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