資源簡介
詳細(xì)介紹了極化SAR數(shù)據(jù)協(xié)方差的pauli分解方法含代碼

代碼片段和文件信息
function[]=pauli_cov(c11c22c33c12c13c23str)
%%??使用協(xié)方差矩陣數(shù)據(jù)的?PAULI?分解??(R:HH+VVG:HVB:HH-VV)
if?nargin==6
????str=‘pauli‘;
end
B=[1?0?1;1?0?-1;0?1.414?0]/1.414;%%??原協(xié)方差矩陣中的HV相已經(jīng)有了1.414,所以B中不是2
[s1s2]=size(c11);
pauli_out=zeros(s1s23);
for?ii=1:s1
????for?jj=1:s2
????????cov=[c11(iijj)c12(iijj)c13(iijj);c12(iijj)‘c22(iijj)c23(iijj);c13(iijj)‘c23(iijj)‘c33(iijj)];
????????t=abs(B*cov*B‘);
????????if?t(11)>1
????????????pauli_out(iijj1)=0.9999;
????????else
????????????pauli_out(iijj1)=t(11);
????????end
????????if?t(22)>1
????????????pauli_out(iijj3)=0.9999;
????????else
????????????pauli_out(iijj3)=t(22);
????????end
????????if?t(33)>1
????????????pauli_out(iijj2)=0.9999;
????????else
????????????pauli_out(iijj2)=t(33);
????????end
????end
end
figure;imshow(?(pauli_out));title(str);
????????
?屬性????????????大小?????日期????時(shí)間???名稱
-----------?---------??----------?-----??----
?????文件????????907??2006-01-11?14:37??pauli_cov.m
-----------?---------??----------?-----??----
?????????????????1125????????????????????2
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