clc
clear
Bus=xlsread（‘bus.xlsx‘）;
Branch=xlsread（‘branch.xlsx‘）;
[busnum~]=size（Bus）;
[branchnumrow]=size（Branch）;
soubus=Branch（:2）;
mobus=Branch（:3）;
Vbus=ones（busnum1）;
Vbus1=Vbus;
Ploss=zeros（busnum1）;
Qloss=zeros（busnum1）;
e=1;
i=1;
k=0;
Branch1=Branch;
n=1;
%%?精髓
%%%%%%%%%%%%%%%支路重新排序，各個分支線同時進(jìn)行計算
while?~isempty（Branch1）%%%%T1為排好的支路矩陣。
????m=1;
????[srow]=size（Branch1）;
????????while?s>0
????????????t=find（Branch1（:2）==?Branch1（s3））;%判斷是否是葉子節(jié)點(diǎn)
????????????????if?isempty（t）%空，則是葉子節(jié)點(diǎn)
????????????????????T1（n:）=?Branch1（s:）;
????????????????????%將葉子節(jié)點(diǎn)放入T1中，
????????????????????%且從節(jié)點(diǎn)系統(tǒng)末端向首端進(jìn)行；
????????????????????%第二次由于Branch1排序問題從首端向末端，無差別，因?yàn)橥逻M(jìn)行
????????????????????n=n+1;
????????????????else
????????????????????T2（m:）=?Branch1（s:）;%非葉子節(jié)點(diǎn)
?????????????????????m=m+1;
????????????????end
???????????????s=s-1;
????????end
????????Branch1=T2;
????????T2=[];
end
%%?
%%%%%%%%%%%%%%%%%%%%%%%
while?e>1.0e-07%%%%收斂條件是精度
????%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
????%前推功率
????%從末端向首端推
????%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
????P=zeros（busnum1）;%%存放后續(xù)功率情況
????Q=zeros（busnum1）;
????????for?s=1:branchnum
????????????????i=T1（s2）;
????????????????j=T1（s3）;
????????????????R=T1（s4）;
????????????????X=T1（s5）;
????????????????%按尾節(jié)點(diǎn)讀取Bus數(shù)據(jù)
????????????????Pload=Bus（j2）;
????????????????Qload=Bus（j3）;
????????????????II=（（Pload+P（j））^2+（Qload+Q（j））^2）/（Vbus（j）^2*1000）;
????????????????Ploss（ij）=II*R;
????????????????Qloss（ij）=II*X;
????????????????P（ij）=Pload+Ploss（ij）+P（j）;
????????????????Q（ij）=Qload+Qloss（ij）+Q（j）;
????????????????P（i）=P（i）+P（ij）;
????????????????Q（i）=Q（i）+Q（ij）;
????????end
?????%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
????%后推電壓
????%從首端向末端推
????%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
?????????for?s=branchnum:-1:1
????????????????i=T1（s2）;?
????????????????j=T1（s3）;%存儲推導(dǎo)電壓的順序
????????????????R=T1（s4）;
????????????????X=T1（s5）;
????????????????Vbus（j）=（Vbus（i）-（P（ij）*R+Q（ij）*X）/（Vbus（i）*1000））^2+（（P（ij）*X-Q（ij）*R）/（Vbus（i）*1000））^2;
????????????????Vbus（j）=sqrt（Vbus（j））;
?????????end
????e=max（abs（Vbus1-Vbus））;%精度收斂條件
????Vbus1=Vbus;
???k=k+1;
end


for?i=1:14
????A（i）=i;
end
A=A‘;
plot（AVbus1‘linewidth‘1.5）;
xlswrite（‘OutPower.xlsx‘P）;

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件???????37637??2019-04-04?20:00??14節(jié)點(diǎn)配電網(wǎng)絡(luò).docx
?????文件????????9572??2019-04-09?22:23??branch.xlsx
?????文件????????9173??2019-04-09?22:06??bus.xlsx
?????文件????????2446??2019-04-09?22:21??FourteenPoint.m