clear;clc;
d=[];e=[];
X=[38192744.5770950.141.549.79108;480978061029658.791.9210.5889;27980633.5641047.81.469.810907;38095763.5989851.671.5610.4999;];
%============數(shù)據(jù)的歸一化處理==============================================
[mn]=size（X）;a=[1?8?9?10];b=[2?3?4?5?6?7?11?12?13];
for?k=1:50
????
for?i=1:m
????for?j=1:9
????????x（ib（j））=（X（ib（j））-min（X（:b（j））））/（max（X（:b（j）））-min（X（:b（j））））;
????end
end

for?i=1:m
????for?j=1:4
????????x（ia（j））=（max（X（:a（j）））-X（ia（j）））/（max（X（:a（j）））-min（X（:a（j））））;
????end
end

N=400;Pc=0.8;Pm=0.2;M=10;Ci=7;n=13;DaiNo=2;ads=1;
[a1b1eeff]=RAGA（xNnPcPmMDaiNoCiads）;
d=[da1];e=[b1;e];
end
[a2?b2]=max（d）e1=e（b2:）
ff=e1*x‘

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件?????????118??2010-03-30?21:19??PP\Feasibility.m
?????文件????????3877??2010-03-30?21:50??PP\RAGA.m
?????文件?????????446??2017-08-08?11:54??PP\Target.m
?????文件?????????753??2010-04-20?15:22??PP\diaoyong.m
?????文件??????612652??2017-08-08?11:24??PP\投影追蹤法.docx
?????文件??????270682??2017-08-08?10:56??PP\綜合評分法的投影尋蹤評標(biāo)方法研究_余賢華.caj
?????目錄???????????0??2017-08-08?12:02??PP\