資源簡介
摘要:全面介紹了區間編碼算法的理論基礎和實現方式。詳細討論了區間編碼原理、正規化操作、區間編碼實現、二進制索引樹的理論和實現等技術。并給出了一個切實可行的應用程序。

代碼片段和文件信息
?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????文件????????7766??2010-10-15?19:33??ArithmeticCoding.dcu
?????文件???????14633??2010-10-15?19:32??ArithmeticCoding.pas
?????文件???????13175??2010-10-15?19:33??CanonicalHuffman.dcu
?????文件???????28284??2010-10-14?14:36??CanonicalHuffman.pas
?????文件????????5548??2010-10-15?19:33??MemoryBuffer.dcu
?????文件???????14558??2010-10-14?14:36??MemoryBuffer.pas
?????文件?????????434??2010-08-26?14:26??Project1.cfg
?????文件????????2358??2010-08-26?14:26??Project1.dof
?????文件?????????360??2010-08-04?13:46??Project1.dpr
?????文件??????435200??2010-10-15?19:33??Project1.exe
?????文件?????????876??2010-06-03?10:19??Project1.res
?????文件????????8174??2010-10-15?19:33??RangeCoding.dcu
?????文件???????16745??2010-10-15?19:32??RangeCoding.pas
?????文件???????19651??2010-10-15?19:33??Unit1.dcu
?????文件??????????51??2010-10-15?19:33??Unit1.ddp
?????文件????????6468??2010-10-15?19:31??Unit1.dfm
?????文件???????17957??2010-10-15?19:32??Unit1.pas
-----------?---------??----------?-----??----
?????文件????????7766??2010-10-15?19:33??ArithmeticCoding.dcu
?????文件???????14633??2010-10-15?19:32??ArithmeticCoding.pas
?????文件???????13175??2010-10-15?19:33??CanonicalHuffman.dcu
?????文件???????28284??2010-10-14?14:36??CanonicalHuffman.pas
?????文件????????5548??2010-10-15?19:33??MemoryBuffer.dcu
?????文件???????14558??2010-10-14?14:36??MemoryBuffer.pas
?????文件?????????434??2010-08-26?14:26??Project1.cfg
?????文件????????2358??2010-08-26?14:26??Project1.dof
?????文件?????????360??2010-08-04?13:46??Project1.dpr
?????文件??????435200??2010-10-15?19:33??Project1.exe
?????文件?????????876??2010-06-03?10:19??Project1.res
?????文件????????8174??2010-10-15?19:33??RangeCoding.dcu
?????文件???????16745??2010-10-15?19:32??RangeCoding.pas
?????文件???????19651??2010-10-15?19:33??Unit1.dcu
?????文件??????????51??2010-10-15?19:33??Unit1.ddp
?????文件????????6468??2010-10-15?19:31??Unit1.dfm
?????文件???????17957??2010-10-15?19:32??Unit1.pas
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