91av视频/亚洲h视频/操亚洲美女/外国一级黄色毛片 - 国产三级三级三级三级

  • 大小: 4KB
    文件類型: .c
    金幣: 1
    下載: 0 次
    發布日期: 2021-07-28
  • 語言: 其他
  • 標簽: ds18b2??89c51??

資源簡介

89c51單片機,實時采集ds18b20溫度,并用1602顯示。也可以設置閾值范圍,到達此范圍溫度,蜂鳴器報警,離開此溫度范圍時,報警停止。

資源截圖

代碼片段和文件信息

/***********************18B20實時溫度計1602顯示***********************
*??晶振:11.0592MHZ
******************************************************************/


#include?
#include?
#include?

#define?uchar?unsigned?char
#define?uint?unsigned?int

sbit?rw?=?P2^1;?
sbit?RS?=?P2^0;??
sbit?LCDEN?=?P2^2;
sbit?ds?=?P2^6;?



void?delayUs()
{
????_nop_();
}

void?delayMs(uint?a)
{
????uint?i?j;
????for(i?=?a;?i?>?0;?i--)
????????for(j?=?100;?j?>?0;?j--);
}


void?writeComm(uchar?comm)????????????//指令寄存器,當rs?rw=0,en由1變成0時,就把P0口的數據送入?
{
?????RS?=?0;????
????P0?=?comm;
????LCDEN?=?1;
?????delayUs();
????LCDEN?=?0;
????delayMs(1);
}

//寫數據:RS=1?RW=0;
void?writeData(uchar?dat)
{
????RS?=?1;
????P0?=?dat;
????LCDEN?=?1;
????delayUs();
????LCDEN?=?0;
????delayMs(1);
}


?void?init()
?{
????rw?=?0;?
????writeComm(0x38);
????writeComm(0x0c);?
????writeComm(0x06);
????writeComm(0x01);?
}

void?writeString(uchar?*?str?uchar?length)
{
????uchar?i;
????for(i?=?0;?i?????{
????????writeData(str[i]);
????}
?}
?
/**//*****************************DS18B20*******************************/

void?dsInit()
?{
????
????unsigned?int?i;??
????ds?=?0;
????i?=?100;??
????while(i>0)?i--;
????ds?=?1;???
????i?=?4;
????while(i>0)?i--;
}
?
void?dsWait()
{
????unsigned?int?i;
????while(ds);??
????while(~ds);
????i?=?4;
????while(i?>?0)?i--;
}


bit?readBit()
{
????unsigned?int?i;
????bit?b;
????ds?=?0;
????i++;???
????ds?=?1;?
????i++;?i++;??
????b?=?ds;
????i?=?8;?
????while(i>0)?i--;
????return?b;
}

unsigned?char?readByte()
{
????unsigned?int?i;
????unsigned?char?j?dat;
????dat?=?0;
????for(i=0;?i<8;?i++)
????{
????????j?=?readBit();
??????
????????dat?=?(j?<>?1);
????}
????return?dat;
}


void?writeByte(unsigned?char?dat)
{
????unsigned?int?i;
????unsigned?char?j;
????bit?b;
????for(j?=?0;?j?????{
????????b?=?dat?&?0x01;
????????da

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