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    文件類型: .zip
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    發(fā)布日期: 2021-12-07
  • 語言: 其他
  • 標(biāo)簽: hypervolume??

資源簡介

多目標(biāo)優(yōu)化的一個性能指標(biāo)-超立方體,它可以測試算法的收斂性也可以測試算法的多樣性。

資源截圖

代碼片段和文件信息

function?res=exi2d(Prmus)
%?P:?approximation?set?2xK?r:?reference?point?mu:?mean?vector?s:stdev
%?vector
%?Example:?exi2d([02;11;20][33][00][0.10.1])?should?approximately
%?result?in?3
%?
%?determine?all?lower?left?corner?cell?coordinates
S=sortrows(P);
k=length(S);

c2?=?sort(S(:2));
c1?=?sort(S(:1));

for?i=0:k?????%?hoogte?van?beneden?naar?boven;?hight?from?below?to?above
????for?j=0:(k-i)?%?first?coordinate?(length)?of?cell?grid
????????%?c1(i)?c2(j)?are?now?the?cell?coordinates?according?Fig.?2???
????????%?For?coordinate?j?determine?hight?fMax2?
????????if?(j==0)?fMax2=r(2);?else?fMax2?=?c2(k+1-j);?end;
????????%?For?coordinate?i?determine?the?width?of?the?staircase?fMax1?
????????if?(i==0)?fMax1=r(1);?else?fMax1?=?c1(k+1-i);?end;
????????%?get?cell?coordinates
????????if?(j==0)?cL1=?-inf;?else?cL1?=?c1(j);?end;?
????????if?(i==0)?cL2=?-inf;?else?cL2?=?c2(i);?end;
????????if?(j==k)?cU1?=?r(1);?else?cU1?=?c1(j+1);?end;
????????if?(i==k)?cU2?=?r(2);?else?cU2?=?c2(i+1);?end;
????????%?SM?=?points?that?are?dominated?or?equal?to?upper?cell?bound??
????????SM=[;];?
????????for?m=1:k
????????????if?(cU1?<=?S(m1)?&&?cU2?<=?S(m2))
????????????????SM=[[S(m1)S(m2)];SM];
????????????end?????????????
????????end
????????sPlus?=?hvolume2d(SM?[fMax1fMax2]);
????????%Marginal?integration?over?the?length?of?a?cell
????????Psi1?=?exipsi(fMax1cU1mu(1)s(1))?-?exipsi(fMax1cL1mu(1)s(1));
????????%Marginal?integration?over?the?height?of?a?cell
????????Psi2?=?exipsi(fMax2cU2mu(2)s(2))?-?exipsi(fMax2cL2mu(2)s(2));
????????%Cumulative?Gaussian?over?length?for?correction?constant
????????GaussCDF1?=?gausscdf((cU1-mu(1))/s(1))?-?gausscdf((cL1-mu(1))/s(1));
????????%Cumulative?Gaussian?over?length?for?correction?constant
????????GaussCDF2?=?gausscdf((cU2-mu(2))/s(2))?-?gausscdf((cL2-mu(2))/s(2));
????????%ExI?Kontribution?fuer?die?aktuelle?Zelle
????????c(i+1j+1)=?Psi1*Psi2-sPlus*GaussCDF1*GaussCDF2;
????end
end

res=sum(sum(max(c0)));

?屬性????????????大小?????日期????時間???名稱
-----------?---------??----------?-----??----
?????目錄???????????0??2010-04-28?15:05??HV_based_expected_improvement\
?????文件????????2033??2010-04-27?19:14??HV_based_expected_improvement\exi2d.m
?????文件??????????80??2010-04-26?22:21??HV_based_expected_improvement\exipsi.m
?????文件??????????51??2010-04-27?18:50??HV_based_expected_improvement\gausscdf.m
?????文件??????????59??2010-04-27?18:46??HV_based_expected_improvement\gausspdf.m
?????文件?????????339??2010-04-26?22:21??HV_based_expected_improvement\hvolume2d.m
?????文件????????1283??2010-04-27?19:29??HV_based_expected_improvement\README.txt

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